Answer:
44.47 cm² (nearest hundredth)
Step-by-step explanation:
Area of ΔABC = 1/2 x base x height
⇒ 21 = 1/2 x 7 x BC
⇒ BC = 6 cm
Pythagoras' Theorem: a² + b² = c²
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
⇒ AB² + BC² = AC²
⇒ 7² + 6² = AC²
⇒ AC² = 85
⇒ AC = √85 cm
Cosine rule to find length AD:
c² = a² + b² - 2 ab cosC
⇒ DC² = AD² + AC² - 2(AD)(AC)cos(DAC)
⇒ 9.2² = AD² + (√85)² - 2(AD)(√85)cos 73°
⇒ AD² - 5.39106...AD + 0.36 = 0
⇒ AD = 5.323442445, 0.06762541414
⇒ AD = 5.323442445
Area of a triangle ADC: (1/2)absinC
(where a and b are adjacent sides and C is the angle between them)
⇒ area = (1/2) × AC × AD × sin(DAC)
⇒ area = (1/2) × √85 × 5.323442445 × sin(73°)
⇒ area =23.4675821... cm²
Area of quadrilateral = area of ΔABC + area of ΔADC
= 21 + 23.4675821...
= 44.47 cm² (nearest hundredth)
You can substitute the value of y(5/6 x + 1) from the first equation for y in the second and get
which becomes
and you get
<u><em>5h+9 is the right answer. </em></u> First you had to used group like terms, and it gave us, 
. Then add similar elements, and it gave us, 
, or 
. Finally, you had to add by the numbers, and it gave us, 
, or and it gave us the answer is 5h+9 is the right answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie
I would be happy to help!
To start off you need to find the amount of koalas there are at the current number of trees by using the ratio one to 3 which means there is one koala for every 3 gum trees. So you need to devide 252 by 3 giving you the answer of 84 koalas currently. Now you nees to find how many koalas there are for the future 345 trees based on the same ratio 1 to 3. This would give you 115 koalas to be expected in the future. Finally to find the amount of koalas increaed you need to subtract 84 from 115 giving you a final answer of 31 koalas.
Answer:
Parallelogram: Yes
Rectangle: No
Quadrilateral: Yes
Pentagon: No
Step-by-step explanation:
HAPPY RAMADAN TO YOU TOO :)
and have you heard of counting stars
