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egoroff_w [7]
2 years ago
9

Two trains are traveling in opposite directions between Los Angeles and Sacramento. The Sacramento bound train is moving at a sp

eed of 60mph and the Los Angeles bound train is moving at a speed of 80mph. Sacramento bound train leaves at 7am and the Los Angeles bound train leaves at 9am. When would these two trains meet if the distance between cities is 400 miles?
Mathematics
1 answer:
salantis [7]2 years ago
6 0

Answer:

Both trains meet at 10 am.

Step-by-step explanation:

<em>Step 1: Find the time Los Angeles bound train takes to travel 400 miles</em>

Speed = 80 mph

Distance = 400

Time = T1

Train leaves at 9 am

Time = Distance/Speed

Time = 400/80

Time = 5 hours

<em>Step 2: Find the time Sacramento bound train takes to travel 400 miles</em>

Speed = 60 mph

Distance = 400 miles

Time = T2

Train leaves at 7 am

Time = Distance/Speed

Time = 400/60

Time = 6.67 hours

<em>Step 3: Calculate the time when both trains will meet</em>

<u>Los Angeles bound train</u>

Leaves at 9 am

1 hour at 10 am

2 hours at 11 am

3 hours at 12 pm

4 hours at 1 pm

5 hours at 2 pm (reaches destination)

<u>Sacramento bound train</u>

Leaves at 7 am

1 hour at 8 am

2 hours at 9 am

3 hours at 10 am

4 hours at 11 am

5 hours at 12 pm

6 hours at 1 pm

7 hours at 2 pm

Both trains will meet at 10 am where the Los Angeles bound train reaches in 1 hour and the Sacramento bound train reaches in 3 hours.

!!

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.
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Answer:

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Step-by-step explanation:

Data given and notation  

\bar X=2.2 represent the sample mean

s=0.29 represent the sample standard deviation

n=40 sample size  

\mu_o =2.1 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.1  

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If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

P-value

The first step is calculate the degrees of freedom, on this case:  

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Since is a one side test the p value would be:  

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