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3 years ago

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Two trains are traveling in opposite directions between Los Angeles and Sacramento. The Sacramento bound train is moving at a sp

eed of 60mph and the Los Angeles bound train is moving at a speed of 80mph. Sacramento bound train leaves at 7am and the Los Angeles bound train leaves at 9am. When would these two trains meet if the distance between cities is 400 miles?

1 answer:

salantis [7]3 years ago

6 0

Answer:

Both trains meet at 10 am.

Step-by-step explanation:

<em>Step 1: Find the time Los Angeles bound train takes to travel 400 miles</em>

Speed = 80 mph

Distance = 400

Time = T1

Train leaves at 9 am

Time = Distance/Speed

Time = 400/80

Time = 5 hours

<em>Step 2: Find the time Sacramento bound train takes to travel 400 miles</em>

Speed = 60 mph

Distance = 400 miles

Time = T2

Train leaves at 7 am

Time = Distance/Speed

Time = 400/60

Time = 6.67 hours

<em>Step 3: Calculate the time when both trains will meet</em>

<u>Los Angeles bound train</u>

Leaves at 9 am

1 hour at 10 am

2 hours at 11 am

3 hours at 12 pm

4 hours at 1 pm

5 hours at 2 pm (reaches destination)

<u>Sacramento bound train</u>

Leaves at 7 am

1 hour at 8 am

2 hours at 9 am

3 hours at 10 am

4 hours at 11 am

5 hours at 12 pm

6 hours at 1 pm

7 hours at 2 pm

Both trains will meet at 10 am where the Los Angeles bound train reaches in 1 hour and the Sacramento bound train reaches in 3 hours.

!!

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Write a rule to describe the function shown. x y −6 −4 −3 −2 0 0 3 2 y equals start fraction two over three end fraction x y equ

sertanlavr [38]

Answer:

$y=\frac{2}{3} x$ (y equals start fraction two over three end fraction x)

Step-by-step explanation:

Lest's organize the table values of our function first:

x y

-6 -4

-3 -2

0 0

3 2

The simplest kind of of function is a linear function of the form $y=mx+b$ where $m$ is the slope and $b$ is the y-intercept. Let's us check if our function is a linear one finding its equation and checking that all points are in the line.

The first step to find a linear equation is find the slope of the line; to do it, we are using the slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

where

$m$ is the slope of the line

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

We know from our table that the first and second points are (-6, -4) and (-3, -2) respectively, so $x_1=-6$ , $y_1=-4$ , $x_2=-3$ , and $y_2=-2$ .

Replacing values:

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-2-(-4)}{-3-(-6)}$

$m=\frac{-2+4}{-3+6)}$

$m=\frac{2}{3)}$

Now that we have the slope of our line we can use the point slope formula to complete our linear function:

$y-y_1=m(x-x_1)$

where

$m$ is the slope

$(x_1,y_1)$ are the coordinates of the first point

Replacing values:

$y-y_1=m(x-x_1)$

$y-(-4)=\frac{2}{3)}(x-(-6))$

$y+4=\frac{2}{3)}(x+6)$

$y+4=\frac{2}{3} x+4$

$y=\frac{2}{3} x+4-4$

$y=\frac{2}{3} x$

Now, to check if our function is valid, we can either check if each point satisfies the rule $y=\frac{2}{3} x$ , or we can graph it and check if each lies is in the graph.

Let's check both:

We already know that points (-6, -4) and (-3, -2) satisfy the rule (after all, those were the point we used to came out with the rule in the first place), so we just need to check the points (0, 0) and (3, 2)

- For (0, 0):

$y=\frac{2}{3} x$

$0=\frac{2}{3}(0)$

$0=0$

The point satisfies the rule.

- For (3, 2):

$y=\frac{2}{3} x$

$2=\frac{2}{3} (3)$

$2=2$

The point satisfies the rule.

Since all the points of our table satisfies the rule $y=\frac{2}{3} x$ , we can conclude that the rule describing the function shown is $y=\frac{2}{3} x$ .

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3 years ago

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2x+5y=-3<br>3x-y=21<br>help me

arlik [135]

Problem:
Solve
2
x
+
5
y
=
−
3
;
3
x
−
y
=
21
Steps:
I will try to solve your system of equations.
3
x
−
y
=
21
;
2
x
+
5
y
=
−
3
Step: Solve
3
x
−
y
=
21
for y:
3
x
−
y
+
−
3
x
=
21
+
−
3
x
(Add -3x to both sides)
−
y
=
−
3
x
+
21
−
y
−
1
=
−
3
x
+
21
−
1
(Divide both sides by -1)
y
=
3
x
−
21
Step: Substitute
3
x
−
21
for
y
in
2
x
+
5
y
=
−
3
:
2
x
+
5
y
=
−
3
2
x
+
5
(
3
x
−
21
)
=
−
3
17
x
−
105
=
−
3
(Simplify both sides of the equation)
17
x
−
105
+
105
=
−
3
+
105
(Add 105 to both sides)
17
x
=
102
17
x
17
=
102
17
(Divide both sides by 17)
x
=
6
Step: Substitute
6
for
x
in
y
=
3
x
−
21
:
y
=
3
x
−
21
y
=
(
3
)
(
6
)
−
21
y
=
−
3
(Simplify both sides of the equation)
Answer:
y
=
−
3
and
x
=
6

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