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egoroff_w [7]
3 years ago
9

Two trains are traveling in opposite directions between Los Angeles and Sacramento. The Sacramento bound train is moving at a sp

eed of 60mph and the Los Angeles bound train is moving at a speed of 80mph. Sacramento bound train leaves at 7am and the Los Angeles bound train leaves at 9am. When would these two trains meet if the distance between cities is 400 miles?
Mathematics
1 answer:
salantis [7]3 years ago
6 0

Answer:

Both trains meet at 10 am.

Step-by-step explanation:

<em>Step 1: Find the time Los Angeles bound train takes to travel 400 miles</em>

Speed = 80 mph

Distance = 400

Time = T1

Train leaves at 9 am

Time = Distance/Speed

Time = 400/80

Time = 5 hours

<em>Step 2: Find the time Sacramento bound train takes to travel 400 miles</em>

Speed = 60 mph

Distance = 400 miles

Time = T2

Train leaves at 7 am

Time = Distance/Speed

Time = 400/60

Time = 6.67 hours

<em>Step 3: Calculate the time when both trains will meet</em>

<u>Los Angeles bound train</u>

Leaves at 9 am

1 hour at 10 am

2 hours at 11 am

3 hours at 12 pm

4 hours at 1 pm

5 hours at 2 pm (reaches destination)

<u>Sacramento bound train</u>

Leaves at 7 am

1 hour at 8 am

2 hours at 9 am

3 hours at 10 am

4 hours at 11 am

5 hours at 12 pm

6 hours at 1 pm

7 hours at 2 pm

Both trains will meet at 10 am where the Los Angeles bound train reaches in 1 hour and the Sacramento bound train reaches in 3 hours.

!!

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A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measure SL 42,000 ft
horsena [70]

Answer:

a= 200

b = 210

Step-by-step explanation:

My assumption is, we have to find the length of sides of rectangle

Given

perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)

area = a*b = 42,000 ft^2 (ii)

from eq (1)

2a + 2b = 820

=> 2(a+b) = 820

=> a+b = 820/2

=> a + b = 410

=> a = 410-b   (iii)

putting the value of a in eq(ii), we get

(410-b) *b = 42,000

410b - b^2 = 42,000

0 = b^2 - 410b + 42000

b^2 - 410b + 42000 = 0

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b(b-200)-210(b-200) = 0

(b-200)(b-210) = 0

or

b= 210 and b = 200

if b is larger side than b =210

By putting value of b in eq(iii),

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Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th
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Answer:

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Step-by-step explanation:

Let $x be thee price of each quart of oil and $y be a flat fee for labor.

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Substitute it into the first equation:

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