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Alika [10]
3 years ago
9

Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
7 0
<span>First we have to find the sum and the difference of those polynomials- The sum is: ( 3 x^5y - 2 x^3y^4 - 7 xy^3 ) + ( - 8 x^5y + 2 x^3y^4 + xy^3 ) = 3 x^5 - 2 x^3y^4 - 7xy^3 - 8 x^5y + 2 x^3y^4 + xy^3 = - 5 x^5y - 6 xy^3. And the difference: ( 3 x^5y - 2 x^3y^4 - 7 xy^3 ) - ( - 8 x^5y + 2 x^3y^4 + xy^3 ) = 3 x^5y - 2 x^3y^4 - 7 xy^3 + 8 xy^5 - 2 x^3y^4 - xy^3 = 11 xy^5 - 4 x^3y^4 - 8xy^3. The highest exponent in both polynomials is 5. Answer: The degree of the polynomials is 5.</span>
const2013 [10]3 years ago
7 0

Answer:D

Step-by-step explanation:

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6 0
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Hello pls help meeee
AnnyKZ [126]

The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).

Given that,

The function is (-x+3)/ (3x-2)

We have to find f(1) and f'(x).

Take the function expression

f(x)= (-x+3)/ (3x-2)

Taking x as 1 value

f(1)= (-1+3)/(3(1)-2)

f(1)=2/1

f(1)=1

Now, to get f'(x)

With regard to x, we must differentiate.

f(x) is in u/v

We know

u/v=(vu'-uv')/ v²        (formula)

f'(x)= ((3x-2)(-1)- (-x+3)(3))/ (3x-2)²

f'(x)= ((-3x+2)-(-3x+9))/ 9x²- 12x+4

f'(x)=(-3x+2+3x-9)/ 9x²- 12x+4

f'(x)=2-9/ (9x²- 12x+4)

f'(x)=-7/ (9x²- 12x+4)

Therefore, The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).

To learn more about function visit: brainly.com/question/14002287

#SPJ1

6 0
1 year ago
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