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Gnom [1K]
4 years ago
12

A trapezoid in Quadrant III rotates 180° clockwise about the origin. What effect does the rotation have on the signs of the coor

dinates? A) The signs change from negative to positive. B) The signs change from positive to negative. C) Only the x-coordinate's sign changes from negative to positive. D) Only the y-coordinate's sign changes from negative to positive.
Mathematics
1 answer:
Ratling [72]4 years ago
4 0

Answer:

A.The signs change from negative to positive.

Step-by-step explanation:

We are given that trapezoid in quadrant III rotates 180 degrees clockwise about the origin.

We have to find the effect of rotation on the sign of  coordinates .

We know that the transformation rule of rotation 180 degrees about the origin is given by

(x,y)\righatarrow (-x,-y)

When a trapezoid lie in III quadrant then the coordinates of all four points are negative because in III quadrant x and y are both negative.

When the trapezoid rotates 180 degrees clockwise about the origin then by using the given rule the sign of coordinates from negative to positive.

Hence, option  A is true.

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PLEASE HELP! (1/4) - 50 POINTS -
Annette [7]

Answer:

  D)  0.35

Step-by-step explanation:

The table gives the area between z=0 and the given magnitude of z. That is, the area between z = 0 and z = -0.6 is 0.23, as found in the 0.6 column of the table. Similarly, the area between z = 0 and z = 0.3 is 0.12, as found in the 0.3 column of the table.

The area between z = -0.6 and z = +0.3 is the sum of these areas:

  p(-.6<z<.3) = 0.23 +0.12 = 0.35

5 0
3 years ago
Tabitha and her parents drive to Dallas for a wedding. After 90 minutes, Tabithas father tells Her they have traveled 105 miles
Dmitriy789 [7]
Remember distance divided by time so 105/90 =1.17
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4 years ago
Find the length of diagonal HJ. Round to the nearest hundredth.
Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}, where

 (x_{1},y_{1}) and (x_{2},y_{2}) are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ x_{1}=-4 and x_{2}=5

∴ y_{1}=3 and y_{2}=-3

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = \sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}

∴ HJ = \sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

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ryzh [129]

Answer:

A centimeter is 100 times the length of a meter.

A kilometer is 1,000 times the length of a meter.

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3 years ago
Find the value of x and y. SHOW YOUR WORK
Leona [35]

Answer:

x=21, y= 35

Step-by-step explanation:

3x+7=5x-35

(subtract seven from -35)

3x=5x-42

(subtract 5 from 3)

-2x=-42

(-42/-2= positive number)

x=21

y+75=3y+5

(subtract 75 from 5)

y=3y-70

(subtract 3y from y)

-2y=-70

y=35

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3 years ago
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