14c³d²-21c²d³/14cd
= (196c^4d³-21c²d³)/ 14cd
= (196c³d²-21cd²)/14
= (28c³d²-3cd²)/2
I hope that's help !
I've answered your other question as well.
Step-by-step explanation:
Since the identity is true whether the angle x is measured in degrees, radians, gradians (indeed, anything else you care to concoct), I’ll omit the ‘degrees’ sign.
Using the binomial theorem, (a+b)3=a3+3a2b+3ab2+b3
⇒a3+b3=(a+b)3−3a2b−3ab2=(a+b)3−3(a+b)ab
Substituting a=sin2(x) and b=cos2(x), we have:
sin6(x)+cos6(x)=(sin2(x)+cos2(x))3−3(sin2(x)+cos2(x))sin2(x)cos2(x)
Using the trigonometric identity cos2(x)+sin2(x)=1, your expression simplifies to:
sin6(x)+cos6(x)=1−3sin2(x)cos2(x)
From the double angle formula for the sine function, sin(2x)=2sin(x)cos(x)⇒sin(x)cos(x)=0.5sin(2x)
Meaning the expression can be rewritten as:
sin6(x)+cos6(x)=1−0.75sin2(2x)=1−34sin2(2x)
Answer:
It’s 5 mph I would be tired if I had to walk 4 miles
5
Step-by-step explanation:
Answer: 3km 42n
Add 2km 35m and 1km 7m together. This will give you your answer of 3km 42n
Hope this helps comment below for more questions :)
Slope = (y2-y1)/(x2-x1)
The points: (2,0) and (0,3)
(3-0)/(0-2) = 3/-2 = -3/2
The solution is -3/2
