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Ymorist [56]
2 years ago
9

What is the common ratio for the geometric sequence? 35/2, 7, 14/5, 28/25, ..…

Mathematics
1 answer:
LiRa [457]2 years ago
8 0

Answer:

2/5

Step-by-step explanation:

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shelia has 5 times more markers then dave and together they have 18 markers how many markers does sheli have?
ryzh [129]
She has 90 markers because 18 times 5 is 90
6 0
3 years ago
Graph f(x)=|x−2|+3 .<br><br> Use the ray tool to graph the function.
maks197457 [2]

Answer:

Answer:

The graph will be 2 units away from the origin on positive x-axis and three units upward from the origin towards y-axis.

Step-by-step explanation:

Here is a graph attached with it.

To graph \left | x-2 \right |+3 we know that positive \left | x \right | is a V shaped from the origin.

Key points:

  • To move rightward there must be a negative inside the parentheses.
  • And to move upward we must have positive b = constant.

If we have to move towards x-axis then we must have negative inside it.

And if we have to move upward in y-axis positive we must have positive constant value.

So the graph will be three units upward and two units rightward with a V-shaped ray.

4 0
3 years ago
Simplify each algebraic axpression 4y+6y+5x-2y<br><br><br>​
Mkey [24]

Answer:

8y+5x

If in the case you need any other help , let me know. [ You need to pay me] :) Thanks!

7 0
1 year ago
Read 2 more answers
Fission tracks are trails found in uranium-bearing minerals, left by fragments released during fission events. An article report
Harlamova29_29 [7]

Answer:

Mean track length for this rock specimen is between 10.463 and 13.537

Step-by-step explanation:

99% confidence interval for the mean track length for rock specimen can be calculated using the formula:

M±\frac{t*s}{\sqrt{N}} where

  • M is the average track length (12 μm) in the report
  • t is the two tailed t-score in 99% confidence interval (2.977)
  • s is the standard deviation of track lengths in the report (2 μm)
  • N is the total number of tracks (15)

putting these numbers in the formula, we get confidence interval in 99% confidence as:

12±\frac{2.977*2}{\sqrt{15}} =12±1.537

Therefore, mean track length for this rock specimen is between 10.463 and 13.537

4 0
3 years ago
Given that a = 10,
tankabanditka [31]

Since a = 10 and b = 2x + 5, we have

ab=10(2x+5)=20x+50

So, the equation becomes

ab = 6x^2 +11x-10 \iff 20x+50= 6x^2 +11x-10 \iff 6x^2-9x-60=0

The solutions to this equation are 4 and -5/2, so I'm afraid there's a typo in your question.

3 0
3 years ago
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