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Ad libitum [116K]
3 years ago
8

joanne's Dress Shop received an invoice dated July 25 for $1400, with terms of 2/10, 1/15, n/60. August 8, Joanne's Dress Shop s

ent a partial payment of $750. The actual amount that should be credited is
Mathematics
2 answers:
Vinvika [58]3 years ago
5 0
642.42 is owed on the 60th day. 
ELEN [110]3 years ago
3 0
642.42 is the correct answer
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HELPPP NEED IN THE NEXT 10 MINSSS!!!!
Mice21 [21]

Answer:

15.6

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Pls help this is for math ill give a brainly​
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Name the shapes that are being described.
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3 years ago
Write 60 as the product of two factors
Ilya [14]
Use a factor<span> tree to express </span>60<span> as a </span>product<span> of prime </span>factors<span>. So the prime factorization of </span>60<span> is 2 × 2 × 3 × 5, which can be written as 2 </span>2<span> × 3 × 5.</span>
5 0
3 years ago
Write a polynomial function, p(x) with degree 3 that has p(7)=0
MArishka [77]

Answer:

p (x) = x^{3} - 21x^{2}+ 147x - 343

is the required polynomial with degree 3 and p ( 7 ) = 0

Step-by-step explanation:

Given:

p ( 7 ) = 0

To Find:

p ( x ) = ?

Solution:

Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.

Therefore zero's of the polynomial is seven i.e 7

Degree : Highest raise to power in the polynomial is the degree of the polynomial

We have the identity,

(a -b)^{3} = a^{3}-3a^{2}b +3ab^{2} - b^{3}

Take a = x

        b = 7

Substitute in the identity we get

(x -7)^{3} = x^{3}-3x^{2}(7) +3x(7)^{2} - 7^{3}\\(x -7)^{3} = x^{3}-21x^{2} +147x - 343

Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.

p ( 7 ) = 7³ - 21×7² + 147×7 - 7³

p ( 7 ) = 0

p (x) = x^{3} - 21x^{2}+ 147x - 343

4 0
3 years ago
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