All categories

3 years ago

Each equation below is followed by several stories.

Mathematics

1 answer:

zloy xaker [14]3 years ago

7 0

Not sure sorry edit : oh sorry I was suppose to add this in the comment section

You might be interested in

Given deductions for this week: federal tax $61.34, FICA $52.05, and state $7.92 what is the annual federal tax deduction?

stealth61 [152]

Given the weekly deductions raised, the annual Federal Tax deduction is $ 3,189.68.

Given that the deductions for the week were: Federal Tax $ 61.34, FICA $ 52.05, and State $ 7.92; To determine what is the annual Federal Tax deduction, the following calculation must be performed:

The weekly deduction must be multiplied by the number of weeks that a year has, to obtain the final amount of taxes.

$ 61.34 x 52 = X
$ 3,189.68 = X

Therefore, the annual Federal Tax deduction is $ 3,189.68.

Learn more in brainly.com/question/25225323

8 0

2 years ago

The half-life of cesium-137 is 30 years. Suppose we have a 180-mg sample. (a) Find the mass that remains after t years. (b) How

DedPeter [7]

Answer:

a) $Q(t) = 180e^{-0.023t}$

b) 11.4mg of cesium-137 remains after 120 years.

c) 225.8 years.

Step-by-step explanation:

The following equation is used to calculate the amount of cesium-137:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t years, Q(0) is the initial amount, and r is the rate at which the amount decreses.

(a) Find the mass that remains after t years.

The half-life of cesium-137 is 30 years.

This means that Q(30) = 0.5Q(0). We apply this information to the equation to find the value of r.

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-30r}$

$e^{-30r} = 0.5$

Applying ln to both sides of the equality.

$\ln{e^{-30r}} = \ln{0.5}$

$-30r = \ln{0.5}$

$r = \frac{\ln{0.5}}{-30}$

$r = 0.023$

$Q(t) = Q(0)e^{-0.023t}$

180-mg sample, so Q(0) = 180

$Q(t) = 180e^{-0.023t}$

(b) How much of the sample remains after 120 years?

This is Q(120).

$Q(t) = 180e^{-0.023t}$

$Q(120) = 180e^{-0.023*120}$

$Q(120) = 11.4$

11.4mg of cesium-137 remains after 120 years.

(c) After how long will only 1 mg remain?

This is t when Q(t) = 1. So

$Q(t) = 180e^{-0.023t}$

$1 = 180e^{-0.023t}$

$e^{-0.023t} = \frac{1}{180}$

$e^{-0.023t} = 0.00556$

Applying ln to both sides

$\ln{e^{-0.023t}} = \ln{0.00556}$

$-0.023t = \ln{0.00556}$

$t = \frac{\ln{0.00556}}{-0.023}$

$t = 225.8$

225.8 years.

8 0

3 years ago

Read 2 more answers

The time is takes to drive between two cities varies inversely

zmey [24]

Answer:

3.5 hour driving at 65 miles per hour

8 0

3 years ago

Slove for x how do u that

pashok25 [27]

What’s the equation

7 0

3 years ago

Read 2 more answers

Hallo! I have a question for you to answer! Please answer if you can C: its worth 10 points and brainliest!

8090 [49]

Answer:

2 2/5

Step-by-step explanation:

3/4 divided by 5/16 = 3/4 times 16/5, which equals 48/20.

4 goes into each.

thus, giving you 12/5.

we write this as a mixed number, which gives us 2 2/5

4 0

3 years ago