Answer:
80,00
Step-by-step explanation:
According to my research, the formula for the Area of a rectangle is the following,

Where
- A is the Area
- L is the length
- W is the width
Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>
800 / 2 = 400ft
So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.
400/2 = 200 ft
Now we can calculate the maximum Area using the values above.


So the Maximum area we are able to create with 800 ft of fencing is 80,00
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Answer:
Step-by-step explanation:
find all of tehe factors to both numbers
15x = 5 3 x
35 = 5 7
pull 5 out of both of them and put the remaining factors in parentheses
5(3x + 7)
Answer:
y= 2× +4
Step-by-step explanation:
Slope intercept form y = mx +b
4x -2y = -8
-2y = -4x-8
y = 2x +4
slope = 2x
y intercept = 4
CB is equal to 10m you can tell this bye the side DC being 20 m and the angle of DC is half of CB so that means that CB has to be 10 m
I'll help with a few.
3. -3x^3 - 9x^2 + 3x
Solve:
= (-3x)(x^2 + 3x + -1)
= (-3x)(x^2)+(-3x)(3x)+(-3x)(-1)
= -3x^3 - 9x^2 + 3x
7. (m - 2) (m + 11)
8. (t - 2) (5t + 9)
9. (5x + 3) (5x - 3)
10. (3t + 2)^2