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Oduvanchick [21]
3 years ago
13

Answer? 2xy+4xy(1+8-7+32)21xy

Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0

The answer is 2xy + 2856x^2y^2


Cymath.com works wonders my friend.

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12.2​z ​+ 19.4 = -2.7​z​ + 93.9
Digiron [165]

Answer:

z=5

Step-by-step explanation:

12.2z​+ 19.4 = -2.7​z​ + 93.9

14.9z=74.5

z=5

3 0
3 years ago
Read 2 more answers
2x^3 + 3x^2 -11x -6 divided by x - 2
Gnesinka [82]

p(x)= x-2

g(x)= 2x^3 + 3x^2 - 11x - 6

first we have to find the zero of the polynomial of x-2

p(x)= x-2 = 0

         x=2

therefore,

p(x)= 2x^3 + 3x^2 - 11x - 6

p(2)= 2*2^3 + 3*2^2 - 11*2 - 6

      = 2*8 + 3*4 - 11*2 - 6

      = 16 + 12 - 22 - 6

      = 28-28

     = 0

Hope it helped u, ^_^.

3 0
2 years ago
Find the coordinates of a point on a circle with radius 18 corresponding to an angle of 190°
devlian [24]

The coordinates of a point on a circle with radius 18 corresponding to an angle of 190° are (-17.73, -3.13).

What is transforming coordinates?

Polar coordinates (r,θ) are transformed into Cartesian coordinates (x, y) using the formulas x = r cos(θ), and y = r sin(θ).

This problem is under the concept of transforming polar coordinates (r,θ) to cartesian coordinates  (x, y).

For this problem the polar coordinates  are r = 18 and θ = 190°.

Convert these polar coordinates into a cartesian coordinates as,

x = r cos(θ) = 18 cos(190°) = -17.73

y = r sin(θ) = 18 sin(190°) = -3.13

The coordinates of a point on a circle with radius 18 corresponding to an angle of 190° are (-17.73, -3.13).

To know more about the transforming coordinates, click on the below link

brainly.com/question/2689696

#SPJ13

8 0
11 months ago
What are the x and y intercepts for 2x-6y=12 and how do you find them?<br> Thanks!
quester [9]
X intercept is
\frac{  2}{6} x
y intercept is 2

3 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
VladimirAG [237]

Answer:

\boxed{108\sqrt{3}\text{ in}^{2}}

Step-by-step explanation:

An apothem is a perpendicular drawn from the centre of the triangle to one of its sides.

The three apothems OD, OE, and OF divide  ∆ABC into six smaller congruent triangles.

1. Area of ∆OCD

CotOCD = OD/OC

cot30 = CD/6

√3 = CD/6

CD = 6√3

A= ½bh

A = ½ × 6√3 × 6 = 18√3  in²

2. Area of ∆ABC

A = 6 × area of ∆OCD = 6 × 18√3 = 108√3 in²

\text{The area of the triangle is }\boxed{108 \sqrt{3} \text{ in}^{2}}

7 0
3 years ago
Read 2 more answers
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