Consolidate (group together) the s terms and then do the same thing to the constant terms:
-2s - (3/4)s = 13 - 2
11
Then (-2 3/4)s = 11, and s = ---------------- = -4 (answer)
-11/4
Answer:
estimating it's 548/9
Step-by-step explanation:
Nitrogen (N) has a molar mass of about 14.007 g/mol, so you have
100.0 g N₂ = (100.0 g) • (1/28.014 mol/g) ≈ 3.570 mol N₂
Hydrogen (H) has a molar mass of about 1.008 g/mol, so
100.0 g H₂ = (100.0 g) • (1/2.016 mol/g) ≈ 49.60 mol H₂
In the balanced reaction, 1 mole of N₂ reacts with 3 moles of H₂ to make 2 moles of NH₃. We have
3.570 • 3 ≈ 10.71
so the reaction would use up all 3.570 mol N₂ and 10.71 mol H₂ to produce about 7.139 mol NH₃.
(A) H₂ is the excess reactant. There is an excess of 49.60 - 10.71 ≈ 38.89 mol H₂.
(B) N₂ is the limiting reactant. All of the N₂ gets consumed in the reaction.
(C) NH₃ has a molar mass of (14.007 + 3 • 1.008) g/mol = 17.031 g/mol. This reaction would theoretically yield about 7.139 mol NH₃, or
7.139 mol NH₃ = (7.139 mol) • (17.031 g/mol) ≈ 121.6 g NH₃
Well theres more than 1 location.. you would have 2 obstacles at 2/6, 4/6, and 6/6. If im Correct
Because Theres
I <u>IO</u> I <em>L</em> <u>IO</u> I <u>IO</u>
1 <u>2</u> 3 <em>Hurdle</em><u> 4</u> 5 <u>6</u>
The I are the Tires
The L is hurdles
and the O is Cones
