Question

How many sets of two or more consecutive positive integers can be added to obtain a sum of 1800?

Answer 1

Answer:

n = 60

Step-by-step explanation:

GIVEN DATA:

Total sum of consecutive number is 1800

sum of n number is given as

$sum = \frac{ n(n+1)}{2}$

where n is positive number and belong to natural number i.e 1,2,3,4,...

from the data given we have$1800 = \frac{n(n+1)}{2}$

solving for n we get

[/tex]n^2 + n -3600 = 0[/tex]

n = 59.5, -60.5

therefore n = 60