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artcher [175]
3 years ago
9

How many sets of two or more consecutive positive integers can be added to obtain a sum of 1800?

Mathematics
1 answer:
Nataliya [291]3 years ago
4 0

Answer:

n = 60

Step-by-step explanation:

GIVEN DATA:

Total sum of consecutive number is 1800

sum of n number is given as

sum = \frac{ n(n+1)}{2}

where n is positive number and belong to natural number i.e 1,2,3,4,...

from the data given we have1800 = \frac{n(n+1)}{2}

solving for n we get

[/tex]n^2 + n -3600 = 0[/tex]

n = 59.5, -60.5

therefore n = 60

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Okay to solve this problem you would simply do this solution. It took me a minute, haven't had to do integers in a while. :D

From 10,000 to 99,999 the numbers divisible by 5 ends in 0 or 5.
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The 2nd digit can be any of 10.
The 3rd digit can be any of 10.
The 4th digit can be any of 10.
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<span>That's 9(10)(10)(10)2=18,000
</span>
I hope this helps. 
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Step-by-step explanation:

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