CaCO₃ + 2HCl = CaCl₂ + CO₂ + H₂O
n(CaCO₃)=m(CaCO₃)/M(CaCO₃)
n(CaCO₃)=13.00/100.09=0.1299 mol
Δm=13.00+52.65-60.32=5.33 g
m(CO₂)=5.33 g
n(CO₂)=5.33/44.01=0,1211 mol
w=0.1211/0.1299=0,9323 (93.23%)
D. LiOH will not produce O2 gas when it decomposes
2.17 x 10²³molecules
Explanation:
Given parameters:
Number of moles of water = 0.36moles
Unknown:
Number of molecules in a water sample = ?
Solution:
A mole of substance is the amount of substance that contains the Avogadro's number of particles which is 6.02 x 10²³ particles.
The particles are molecules, formula units, number of protons, neutrons, electrons, e.t.c;
Since 1 mole of any substance = 6.02 x 10²³ molecules
0.36 moles of water = 0.36 x 6.02 x 10²³ = 2.17 x 10²³molecules
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