Ksp=3.45×10⁻¹¹
CaF₂(s) ⇄ Ca²⁺(aq) + 2F⁻(aq)
Ksp=[Ca²⁺][F⁻]²
[Ca²⁺]=C(CaF₂)
[F⁻]=2C(CaF₂)
Ksp=4{C(CaF₂)}³
C(CaF₂)=∛(Ksp/4)
C(CaF₂)=∛(3.45×10⁻¹¹/4)=2.05×10⁻⁴ mol/L
2.05×10⁻⁴ M
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The Answer is C
It's found inside of a cell attached to the cytoplasm and attached to the endoplasmic reticulum. hope this helps
Good questions,ideas,and observations
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The products are carbon dioxide and water.