Answer:
7.41 × 10⁻⁵
Explanation:
Let's consider the basic dissociation reaction of trimethylamine (CH₃)N).
(CH₃)N + H₂O = (CH₃)NH⁺ + OH⁻
According to Brönsted-Lowry, in this reaction (CH₃)N is a base and (CH₃)NH⁺ is its conjugate acid. The pKb for (CH₃)N is 9.87. We can calculate the pKa of (CH₃)NH⁺ using the following expression.
pKa + pKb = 14
pKa = 14 - pKb = 14 - 9.87 = 4.13
Then, we can calculate the acid dissociation constant for (CH₃)NH⁺ using the following expression.
pKa = -log Ka
Ka = antilog - pKa = antilog -4.13 = 7.41 × 10⁻⁵
Answer:
2.00 M
Explanation:
The formula mass of aluminum oxide is 2(27)+3(16)=102 g/mol.
So, there is 1 mole of solute in 500 mL=0.5 L of solution
Now, we can use the equation molarity = (moles of solute)/(liters of solution)
- molarity = 1/0.5 = <u>2.00</u><u> </u><u>M</u>
Electrons are negative protons are positive you remove or add on to the balance is shifted and the electrical charge is changed
