Consider the following balanced thermochemical equation for a reaction sometimes used for H₂S production: 1/8 S₈(s) + H₂(g) → H₂
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Answer : The mass of reactant remain would be, 0.20 grams.
Solution : Given,
Moles of = 0.40 mol
Moles of = 0.15 mol
Molar mass of = 2 g/mole
First we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 1 mole of react with 2 mole of
So, 0.15 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
The moles of reactant remain = 0.40 - 0.30 = 0.10 mole
Now we have to calculate the mass of reactant remain.
Therefore, the mass of reactant remain would be, 0.20 grams.
Answer:
Explanation: you need to remove the subscript of 5
