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saul85 [17]
3 years ago
10

Y - 5 ='3/2(x+4) using that as a fraction write an equation in slope intercept form

Mathematics
2 answers:
grandymaker [24]3 years ago
8 0
Easey
y=mx+b
just solve for y

y-5=3/2(x+4)
y-5=3/2x+12/2
y-5=3/2x+6
add 5 to bot sides
y=3/2x+11
frosja888 [35]3 years ago
4 0
Y-5=3/2(x+4)
y-5= 3/2x +6
y=3/2x+11

Hope this helps :)
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Alternate Exterior

Step-by-step explanation:

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An artist is painting flower pots that each require 1/32 gallon of paint. What is the maximum number of flower pots the artist c
Alex787 [66]

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24 flower pots

Step-by-step explanation:

Fraction of paint required per flower pot = 1/32

Number of pots that can be painted with 3/4 galoons of paint :

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help me pls! The radius of Circle A is 7 mm. The radius of Circle B is 5 mm greater than the radius of Circle A. The radius of C
bazaltina [42]

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3.45 times

Step-by-step explanation:

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5 0
2 years ago
Find the value of XP if X is between P and Q. <br><br> XQ= 3k, XP= 7k - 2, PQ= 6k + 18
VMariaS [17]

If X is between P and Q, then PQ is the whole line segment and XQ and XP are line segments that add up to PQ. Therefore, you can make an equation where XQ and XP add up to PQ.

XQ + XP = PQ

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5 0
3 years ago
Read 2 more answers
An ideal gas is confined within a closed cylinder at a pressure of 2.026 × 105 Pa by a piston. The piston moves until the volume
Elis [28]

Answer:

The final pressure of the gas when its temperature returns to its initial value 1.8234\times 10^6 Pa.

Step-by-step explanation:

Given : An ideal gas is confined within a closed cylinder at a pressure of 2.026\times 10^5 Pa by a piston. The piston moves until the volume of the gas is reduced to one-ninth of the initial volume.

To find : What is the final pressure of the gas when its temperature returns to its initial value?

Solution :

Since the temperature is constant .

The relation between P and V is given by,

P_1\times V_1 = P_2\times V_2

\frac{P_1}{P_2}=\frac{V_2}{V_1} ....(1)

The piston moves until the volume of the gas is reduced to one-ninth of the initial volume i.e. V_2=\frac{V_1}{9}

or \frac{V_2}{V_1}=\frac{1}{9}

P_1=2.026\times 10^5

Substitute in equation (1),

\frac{2.026\times 10^5}{P_2}=\frac{1}{9}

P_2=9\times 2.026\times 10^5

P_2=18.234\times 10^5

P_2=1.8234\times 10^6

The final pressure of the gas when its temperature returns to its initial value 1.8234\times 10^6 Pa.

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