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3 years ago

Find the slope of the line through each pair of units (6,2), (0, -4)

Mathematics

1 answer:

deff fn [24]3 years ago

8 0

Slope equals change in y over change in x, which is rise over run.

-4-2/0-6
-6/-6
1

Final answer: 1

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All numbers greater than or equal to 6

ExtremeBDS [4]

The correct answer is 3 and any number you can really think of that equals 6

8 0

3 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

Find the inverse of this 3x3 matrix. [1 5 2]

MissTica

Lets say the 3x3 Matrix is

M = [1 5 2 ]
[1 1 7 ]
[0 -3 7 ]

We apply the Gauss-Jordan elimination method (Procedure and result shown in the image below)

5 0

3 years ago

Suppose that qequals30, Lequals5, and Kequals15 is a point on the production function qequalsf(L, K). Is it posssible for qe

Kamila [148]

Answer:

Step-by-step explanation:

If q=30, L=5, and K=15 is a point on the production function q=f(L, K).

Production function is an equation that expresses the relationship between the quantities of factors of production used and the amount of product obtained under the assumption that the most efficient available methods of production are used.

The combination q=30, L=5, and K=16 cannot be a point because we assume production functions are efficient.

7 0

3 years ago

Read 2 more answers

-3r +9 = -4r +5<br>what's r?

-BARSIC- [3]

Answer:

-4

Step-by-step explanation:

-3r+9=-4r+5

-3r+4r=5-9

r=-4