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stich3 [128]
2 years ago
14

Find 6889 + 3088 + 9062.

Mathematics
2 answers:
Varvara68 [4.7K]2 years ago
6 0

1903

pls mark brainliest

if u want

nasty-shy [4]2 years ago
4 0

Answer:

19039

Step-by-step explanation:

hope that help mark me brinilylist

you need to explain more

it was easy

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y varies directly as x and inversely as the square of z. y equals y=30 when x equals x=108 and z equals z=6. Find y when x equal
Slav-nsk [51]

Answer:

Step-by-step explanation:

That really easy Peary it’s not eieoruirbcbdkehbdbs shrine chdiej

4 0
3 years ago
Select the correct answer.
blsea [12.9K]

Answer: as the sample size is approximately large, the margin of the error is 0.15

Step-by-step explanation:

4 0
2 years ago
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Multiply.<br><br> (2 − 5i)(3 + i)
ANEK [815]

(2-5i)(3+i)

use foil method to expand it into standard form

6+2i-15i+5i^2

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7 0
3 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
What is the median of the data displayed in this box-and-whisker plot? A.41 B.49 C.55 D.58
Likurg_2 [28]
The answer is A. 41 because it is in the middle of the box.
4 0
3 years ago
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