All categories

3 years ago

Set notation and interval notation: -3 is less than or equal to x, which is less than 5

2 answers:

7 0

The "less than or equal" is represented by the shape $\leq$
The "Less than" is represented by the shape <

So, -3 is less than or equal to x. So $-3 \leq x$
"which is less than 5" (is = x). So x<5

So, we can get the final notation:
$-3 \leq x\ \textless \ 5$

Hope this Helps! :)

ASHA 777 [7]3 years ago

4 0

-3 is less than 5 -3<5

You might be interested in

A repair company’s charge for repairing a certain type of copy machine fits the model y = 47.38 + 0.617x where y is the number o

Tems11 [23]

Answer: 36.66min

Step-by-step explanation:

y = 47.38 + 0.617x

where y is the number of dollars

x is the number of minutes on the job

Given a value of y = $70, then

We substitute y = $70 in the equation.

70 = 47.38 + 0.617x

22.62 = 0.617x

X = 22.62/0.617 = 36.66min

6 0

3 years ago

What is the area of the regular polygon

dalvyx [7]

A regular polygon is equilateral (it has equal sides) and equiangular (it has equal angles). To find the area of a regular polygon, you use an apothem — a segment that joins the polygon's center to the midpoint of any side and that is perpendicular to that side (segment HM in the following figure is an apothem).

3 0

3 years ago

Read 2 more answers

Xavier bought a shirt that was on sale for 20% off the original price. He also used a coupon that gave him an extra 15% off the

just olya [345]

To find the sale price multiply the original cost by the sale percentage. (37x.2= 7.4) subtract this discount from the total (37-7.4= 29.6) this is your sale price. Now multiply this by the other percentage (29.6x.15= 4.44) (29.6-4.44= 25.16) $25.16 is your final answer

4 0

3 years ago

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .

$p_2=0.94$

The total number of shipment, i.e sample size, $n_2= 300$

Here, the sample size is sufficiently large to approximate it as a normal distribution, for which mean, $\mu_2$ , and variance, $\sigma_2^2$ .

Mean: $\mu_2=n_2p_2=300\times0.94=282$

Variance: $\sigma_2^2=n_2p_2(1-p_2)=300\times0.94(1-0.94)=16.92$

$\Rightarrow \sigma_2=\sqrt(16.92}=4.11$ .

In this case, X>285, so, by using the continuity correction, take x=285.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{285.5-282}{4.11}=0.85$ .

So, the probability that a given shipment is acceptable is

$P(z\geq0.85)=\int_{0.85}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}=0.1977$

Hence, the probability that a given shipment is acceptable is 0.20.

(c) For the acceptance of 99% shipment of in the total shipment of 300 (sample size).

The area right to the z-score=0.99

and the area left to the z-score is 1-0.99=0.001.

For this value, the value of z-score is -3.09 (from the z-score table)

Let, $\alpha$ be the required probability of acceptance of one shipment.

So,

$-3.09=\frac{285.5-300\alpha}{\sqrt{300 \alpha(1-\alpha)}}$

On solving

$\alpha= 0.977896$

Again, the probability of acceptance of one shipment, $\alpha$ , depends on the probability of meeting the thickness specification of one bearing.

For this case,

The area right to the z-score=0.97790

and the area left to the z-score is 1-0.97790=0.0221.

The value of z-score is -2.01 (from the z-score table)

Let $p$ be the probability that one bearing meets the specification. So

$-2.01=\frac{439.5-500 p}{\sqrt{500 p(1-p)}}$

On solving

$p=0.9053$

Hence, 90.53% of the bearings meet a thickness specification so that 99% of the shipments are acceptable.

8 0

3 years ago

Rosalina just started a new job. She has $500 in her bank account. Every week, she deposits $40 into her bank account. Write an

Mrrafil [7]

Answer:

10.14 years

Step-by-step explanation:

The following equation describes the percentage of all eligible voters that are registered to vote as a function of time:

V=100-30e^{-0.04t}

The time 't' for which V(t) = 80 is the amount of years required for the percentage of registered voters to reach 80%:

80=100-30e^{-0.04t}\\\frac{20}{30}= e^{-0.04t}\\ln(\frac{2}{3})=-0.04t*ln(e)\\ t=10.14\ years

It will take 10.14 years until 80% of all eligible voters in your county are registered to vote

8 0

3 years ago

Read 2 more answers