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Trava [24]
3 years ago
10

What is the sine cosine and tangent of 360 degrees

Mathematics
1 answer:
Mrac [35]3 years ago
4 0
Sine and cosine has period of 2π and tangent has period of π

So basically same question as sin(0), cos(0), and tan(0)

sin(0) = 0

cos(0) = 1

tan(0) = sin(0) / cos(0) = 0 / 1 = 0

So final answers are sin(360°) = 0, cos(360°) = 1, tan(360°) = 0
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F=5/9c+32<br> Solve for c
arsen [322]
F = (5/9)c + 32
F - 32 = (5/9)c
9(F-32) = 5c

(9(F-32))/5 = c
4 0
3 years ago
Triangle ABC is an isosceles right triangle inscribed in a circle. The center of the circle is point D and the diameter of the c
Paha777 [63]

Answer:

* AD is congruent to DC and BD <em>true</em>

* m∠B = 90° <em>true</em>

<u>* The measure of arc AC is equal to the measure of arc AB </u><u><em>not be true</em></u><em> ( The right answer  )</em>

* The measure of arc AB is equal to measure of arc BC <em>true</em>

Step-by-step explanation:

∵ D is the center of the circle and A , B and C are points on the circle

∴ AD , DB and DC are radii on the circle D

∴ AD ≡ DC ≡ DB

∵ AC passing through point D which is the center of the circle

∴ AC is the diameter of the circle D

∵ ∠B is opposite to the diameter of the circle and vertex B lies on the circle

∵ ∠B is an inscribed angle and  ∠ADC  is a central angle subtended by the same arc AC

∴m∠B = half m∠ADC

∵ m∠ADC = 180°

∴ m∠B = 90°

∵ The measure of arc AC = 180°

∵ ΔABC is isosceles and m∠B = 90°

∴ m∠BAC = m∠BCA = (180° - 90°) ÷ 2 = 45°

∵ ∠ACB is an inscribed angle subtended by arc AB

∴ m∠ACB = half measure of arc AB

∵ The measure of arc AB = 45° × 2 = 90°

∴ The measure of arc AC ≠ the measure of arc AB

∵ Δ ABC is an isosceles triangle and m∠B = 90°

∴ AB = BC

∵ AB subtended by arc AB

∵ BC subtended by arc BC

∴ The length of arc AB = the length of arc BC

∵ If two arcs are equal in length, then they will be equal in measure

∴ The measure of arc AB is equal to the measure of arc BC

3 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Black_prince [1.1K]

Step-by-step explanation:

Statements

1.OD=OC OB=OA

2. measure of DOB equal m COA

3.Triangle DOB is congruent to triangle COA

4.BD equal CA

Reasons

1.radii of same circle is equal

2. Vertical angles are equal

3.SAS

4.CPCTC

5 0
3 years ago
Read 2 more answers
The top of the Boulder Dam has an angle of elevation of 1.2 radians from a point on the Colorado River. Measuring the angle of e
Nana76 [90]

Answer:

382.925 feets

Step-by-step explanation:

The solution diagram is attached below :

Converting radian measurement to degree :

radian angle * 180/π = degree angle

1.2 * 180/π = 68.755°

0.9 * 180/π = 51.566°

Height of dam is h:

Using trigonometry :

Tan θ = opposite / Adjacent

Tan 68.755° = h / x

h = x Tan 68.755° - - - (1)

Tan 51.566° = h / (155+x)

h = (155+x) tan 51.566° - - - (2)

Equate (1) and (2)

x Tan 68.755 = (155+x) Tan 51.566

x Tan 68.755 = 155tan 51.566 + x tan 51.566

x Tan 68.755 = 195.32311 + x Tan 51.566

x Tan 68.755 - x Tan 51.566 = 195.32311

x(tan 68.755 - tan 51.566) = 195.32311

x * 1.3120110 = 195.32311

1.3120110x = 195.32311

x = 195.32311 / 1.3120110

x = 148.87307

Using :

h = x Tan 68.755

h = 148.87307 * tan(68.755)

h = 382.92539

h = 382.925 feets

5 0
3 years ago
HELP ASAP!!! make sure to submit a pic of the graph!
gavmur [86]

Answer:

Good luck with math

4 0
3 years ago
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