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2 years ago

Anyone help ASAP pls!!

Mathematics

2 answers:

egoroff_w [7]2 years ago

5 0

A fraction equal to 1

vladimir1956 [14]2 years ago

3 0

A fraction equal to one. Anything times one is that number so 1 1/3 times 3/3 is 1 1/3

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6p+2+ p - 3 = 8p - 8

saul85 [17]

6p+p+2-3=8p-8
7p-1=8p-8
1=1p-8
7=1p
p=7

7 0

3 years ago

Multiply.

Kamila [148]

Expand the following:
(x - 6) (3 x^2 + 10 x - 1)
Hint: | Multiply out (x - 6) (3 x^2 + 10 x - 1).
| | | | x | - | 6
| | 3 x^2 | + | 10 x | - | 1
| | | | -x | + | 6
| | 10 x^2 | - | 60 x | + | 0
3 x^3 | - | 18 x^2 | + | 0 x | + | 0
3 x^3 | - | 8 x^2 | - | 61 x | + | 6:
Answer: 3 x^3 - 8 x^2 - 61 x + 6 Thus B:

7 0

2 years ago

Please help!! Math problem and I don't know how to do it!! 14 points!!

IgorLugansk [536]

Let Brian's steps have a measure of 1, and Richard's steps have a measure of k. Then after each walks 5 steps away from the other, their distance apart is

... 5 + 5k

We are told that distance is equal to 9 of Richard's steps, so is equal to 9k.

... 5 + 5k = 9k

... 5 = 4k . . . . . . . subtract 5k

... 5/4 = k . . . . . . divide by 4

Richard's steps are 5/4 the size of Brian's steps. The appropriate selection is

... b) 5/4

6 0

2 years ago

Please help, thank you so much !!

Sliva [168]

Answer: x = 54

Explanation:

180 - 14 = 166

3x + 4 = 166
3x = 162
x = 162/3 = 54

6 0

2 years ago

A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa

Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion

p(private) be the proportion of alumni of the private university who attended at least one class reunion

Hypotheses are:

$H_{0}$ : p(public) = p(private)

$H_{a}$ : p(public) ≠ p(private)

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of public university students who attended at least one class reunion ( $\frac{808}{1311}=0.616$ )

p2 is the sample proportion of private university students who attended at least one class reunion ( $\frac{647}{1038}=0.623$ )

p is the pool proportion of p1 and p2 ( $\frac{808+647}{1311+1038}=0.619$ )

n1 is the sample size of the alumni from public university (1311)

n2 is the sample size of the students from private university (1038)

Then z= $\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}}$ =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.

6 0

3 years ago