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3 years ago

Help please and thank you

Mathematics

1 answer:

taurus [48]3 years ago

5 0

Answer:

45.8

Step-by-step explanation:

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Step-by-step explanation:

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Solve the equation 2cosA = 3tanA

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$\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\\\\
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$\bf \\\\\\
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\begin{cases}
0=2sin(A)-1\\
1=2sin(A)\\
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now, as far as the second case....well, sine of anything is within the range of -1 or 1, so -1 < sin(A) < 1

now, we have -2 = sin(A), which simply is out of range for a valid sine, so there's no angle with such sine

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Step-by-step explanation:

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