Expanding 8x^3, we multiply 8*8 and x^3 by x^3 to get 64x^6. Since we know that the cube root of 64 is 4, we can separate that. Next, since you add exponents while multiplying, 6/3 is the exponent for the cube root of x^6=x^2. Therefore, your answer is 4x^2
<span>60
Sorry, but the value of 150 you entered is incorrect. So let's find the correct value.
The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So
(300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500
So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that:
(375+x)(240+x)-90000 = 40500
The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation:
(375+x)(240+x)-90000 = 40500
x^2 + 375x + 240x + 90000 - 90000 = 40500
x^2 + 615x = 40500
x^2 + 615x - 40500 = 0
Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
Answer:
keep the car at a friends house untill you find a place to get it fixed at... or keep it at a trustworthy family members house.
If these don't help then im sorry.
Answer:1.09090909091
Step-by-step explanation:
Answer:
Science class had a higher average
Step-by-step explanation:
Given
g(x) table
Solving (a): f(2)
We have:
So:
Solving (b): g(2)
From the given table.
Solving (c): f(4) or g(4); which is greater
So:
For g(4): Notice that in the table of g(x); g(x) increases by 2 when x increases by 1
This means that:
So
<em>Hence, g(4) i.e. Science class is greater</em>
