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Anestetic [448]
3 years ago
11

Simplify the following radical Sqrt 126x^13

Mathematics
1 answer:
fenix001 [56]3 years ago
3 0

Answer:

\large\boxed{\sqrt{126x^{13}}=3x^6\sqrt{14x}}

Step-by-step explanation:

Domain:\ x\geq0\\\\\sqrt{126x^{13}}=\sqrt{9\cdot14\cdot x^{12+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{9\cdot14\cdot x^{12}\cdot x^1}=\sqrt{9\cdot14\cdot x^{6\cdot2}\cdot x}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\ \text{and}\ (a^n)^m=a^{nm}\\\\=\sqrt9\cdot\sqrt{14}\cdot\sqrt{(x^6)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=3\cdot\sqrt{14}\cdot x^6\cdot\sqrt{x}=3x^6\sqrt{14x}

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Answer:

[11.5-(2.5*3)]^2=16

Step-by-step explanation:

We want to evaluate [11.5-(2.5*3)]^2

Let us evaluate within the parenthesis first:

[11.5-(2.5*3)]^2=[11.5-(7.5)]^2

\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2

We again subtract within the bracket to obtain:

[11.5-(2.5*3)]^2=[4]^2

This finally gives us:

[11.5-(2.5*3)]^2=16

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