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Anestetic [448]
3 years ago
11

Simplify the following radical Sqrt 126x^13

Mathematics
1 answer:
fenix001 [56]3 years ago
3 0

Answer:

\large\boxed{\sqrt{126x^{13}}=3x^6\sqrt{14x}}

Step-by-step explanation:

Domain:\ x\geq0\\\\\sqrt{126x^{13}}=\sqrt{9\cdot14\cdot x^{12+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{9\cdot14\cdot x^{12}\cdot x^1}=\sqrt{9\cdot14\cdot x^{6\cdot2}\cdot x}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\ \text{and}\ (a^n)^m=a^{nm}\\\\=\sqrt9\cdot\sqrt{14}\cdot\sqrt{(x^6)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=3\cdot\sqrt{14}\cdot x^6\cdot\sqrt{x}=3x^6\sqrt{14x}

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Susan and Steven are cousins. The sum of their ages is 33. The difference between three times Steven's age and half of Susan's a
VARVARA [1.3K]
The complete question is
Susan and Steven are cousins. The sum of their ages is 33. The difference between three times Steven's age and half of Susan's age is 36. Find <span>the age of Susan and Steven

let
x-----> </span>Susan's age
y---->  Steven's age

we know that
y+x=33-----> equation 1
3y-x/2=36----> multiply by 2----> 6y-x=72----> equation 2
adds equation 1 and equation 2

y+x=33
6y-x=72
-------------+
7y=105--------> y=15
x=33-y----> x=33-15----> x=18

the answer is
Susan's age is 18
Steven's age is 15

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