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forsale [732]
2 years ago
5

Find the total capacity of 25 containers of cranberry juice if each bottle holds 5 quarts 1 pint 6 oz

Mathematics
1 answer:
kaheart [24]2 years ago
5 0
Find the total capacity of 25 containers of cranberry juice is each bottle holds 5/4 one pant 60Z
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Please I need help I’m not good at math
PolarNik [594]

Answer:

4

Step-by-step explanation:

because you do 2-1 and then 3 * 3 the equation would look like this

1 + (3*3) /

1+9/ 3

1 + 3

4

6 0
2 years ago
Aleksandra started studying how the number of branches in her tree grows over time. Every 1.5 years, the number of branches incr
vova2212 [387]

Answer:

N = 52 * (9/7)^(t/1.5)

Step-by-step explanation:

This problem can be modelated as an exponencial problem, using the formula:

N = Po * (1+r)^(t/1.5)

Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.

In our case, we have that N is the final number of branches after t years, Po = 52 branches, r = 2/7 and t is the number of years since the beginning (in the formula we divide by 1.5 because the rate is defined for 1.5 years)

Then, we have that:

N = 52 * (1 + 2/7)^(t/1.5)

N = 52 * (9/7)^(t/1.5)

7 0
3 years ago
The distance between capeton & Jonesville is 80 miles. The scale on the map is 0.75 in 10 Mi how far part are the cities on
ikadub [295]

Answer:

6 in = 80 miles

Step-by-step explanation:

Given that:

Distance between Capeton and Jonesville = 80 miles.

Map scale : 0.75 in = 10 miles ; this means 0.75 inches on the map represents 10 miles on land.

Hence, If ;

0.75 inches = 10 miles

x inches = 80 miles

Cross multiply :

10 * x = 80 * 0.75

10x = 60

10x / 10 = 60 / 10

x = 6 inches

Hence,

6 in = 80 miles

4 0
3 years ago
How many digits will be behind the decimal point when you find the product of 8.381 x 0.7?
tangare [24]

Answer:

4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
For the straight line defined by the points (4,57) and (6,91) , determine the slope ( m ) and y-intercept ( ???? ). Do not round
Ksivusya [100]

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{57})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{91}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{91}-\stackrel{y1}{57}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{4}}}\implies \cfrac{34}{2}\implies 17 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{57}=\stackrel{m}{17}(x-\stackrel{x_1}{4})\implies y-57=17x-68

\bf y=17x-11\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad \begin{cases} \stackrel{slope}{17}\\\\ \stackrel{y-intercept}{(0,-11)} \end{cases}

4 0
3 years ago
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