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valina [46]
3 years ago
7

Which expression represents the volume of the pyramid? StartFraction x cubed + 2 x squared Over 3 EndFraction cm3 StartFraction

x squared + 2 x squared Over 2 EndFraction cm3 StartFraction x cubed Over 3 EndFraction cm3 StartFraction x cubed + 2 x squared Over 2 EndFraction cm3
Mathematics
2 answers:
saw5 [17]3 years ago
6 0

Answer:

<h3> (x³+2x²)/3 cm³</h3>

Step-by-step explanation:

Find the diagram attached

Volume of a pyramid = 1/3 * Base area * height

Base area = x*x

Base area = x²

Height = x+ 2

Get the volume:

Volume of the pyramid = 1/3 * x² * x+2

Volume of the pyramid =  x²(x+2)/3

<em>Volume of the pyramid  = (x³+2x²)/3 cm³</em>

Yakvenalex [24]3 years ago
4 0

Answer:

D aka (x³+2x²)/3 cm³

Step-by-step explanation:

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Dima020 [189]
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This answer, "Answer choice [D]", is the converse of the conditional statement given: "If x = -10, then x^{2} = 100 . "
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As such, this is the correct answer choice.
5 0
3 years ago
What is the value of p?
anzhelika [568]
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3 0
3 years ago
8y-2(y+4)= i was just wondering the best way to work this
Bond [772]

Answer:

6y-8

Step-by-step explanation:

8y-2(y+4)

8y-2y-8 distribution

6y-8 combined like-terms

4 0
3 years ago
reorder the numbers and combine like terms to simplify 4.5+2 1/2 +6.0-5 1/2 is it A. -7.5 B. 7 C.7.5 or D.8.5​
DerKrebs [107]

Answer:

I believe its C

Step-by-step explanation:

I added them up lol

6 0
3 years ago
Read 2 more answers
For two events, M and N, P(M)=0.7, P(N|M)=0.3, and P(M'|N')
dexar [7]
Topic:C<span>onditional Probability

</span>For any two events A and B, where P(B) ≠ 0, P( A | B ) = P( A ∩ B ) / P( B ) = P( B | A) * P(A) / P(B)..i.e..{the probability of A given B is equal to the probability of A and B divided by the probability of B}

<span>For a set of events A1, A2, A3, ... , An,
</span>hence,
P(B) 
<span>= P(B and A1) + P(B and A2) + ... + P(B and An) </span>
= P(B | A1) * P(A1) + P(B | A2) * P(A2) + ... + P(B | An) * P(An)

P(M | N) 
<span>= P(N | M) * P(M) / P(N) </span>
<span>= P(N | M) * P(M) / (P(N | M) * P(M) + P(N | M') * (1 - P(M))) 
</span><span>Substitute Values.... you get ?

</span>
5 0
3 years ago
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