Which expression represents the volume of the pyramid? StartFraction x cubed + 2 x squared Over 3 EndFraction cm3 StartFraction
2 answers:
Answer:
<h3> (x³+2x²)/3 cm³</h3>Step-by-step explanation:
Find the diagram attached
Volume of a pyramid = 1/3 * Base area * height
Base area = x*x
Base area = x²
Height = x+ 2
Get the volume:
Volume of the pyramid = 1/3 * x² * x+2
Volume of the pyramid = x²(x+2)/3
<em>Volume of the pyramid = (x³+2x²)/3 cm³</em>
You might be interested in
To solve the problem we must know about Like Terms.
<h3>What are Like Terms?</h3>Like terms are those terms that are having the same variables, also the variables are of the same order as well.
for example, 25x and 5x are like terms; 30xy and 7xy are like terms, 9x³ and 4x² are not like terms, etc.
The solution to the problem is (-1.7x-1.3).
Given to us
- f(x) = 3.7 - 2x
- g(x) = 0.25x - 5
To find
f(x) + g(x)
To solve the problem we will put the functions as given to us,
Open brackets,
Solve the like terms,
Hence, the solution to the problem is (-1.7x-1.3).
Learn more about Like Terms:
Answer:
1: C =69.3 m2
2: F = ll units
3. C: 3 in.
4. G =65 units
Step-by-step explanation:
1: C =69.3 m2
We see from the figure that height of the parallelogram ABCD is not known and the base is 10 m
Taking the right angled triangle the height is given by
Sine theta= height/hypotenuse
height = hypotenuse* sine theta
= 8* sine 60
= 8* 0.866= 6.928
Area of parallelogram= base * height
= 10 * 6.928
= 69.28
=69.3 m²
2: F = ll units
We see from the figure that height of the parallelogram DEFG is not known and the base is 13 cm
Area of parallelogram= base * height
143 = 13 * height
Height = 143/13= 11 units
3. C: 3 in.
The area of the triangle = 1/2 * base * height
Let the height be x then the base is 3x
54= 1/2*x*3x
54= 3x²/2
27= 3x²
x²=27/3
x²= 9
x= 3
The height is 3 inches
4. G =65 units
Area of the quadrilateral = 1/2 *PR*QO + 1/2 *PR*OS
= 1/2*13*4+ 1/2*13*6
=26+ 39
= 65 units
These measurements are given in the diagram .
