6a. By the convolution theorem,

6b. Similarly,

7. Take the Laplace transform of both sides, noting that the integral is the convolution of
and
.


where
. Then
, and

We have the partial fraction decomposition,

Then we can easily compute the inverse transform to solve for f(t) :


Answer:
idk either sorry but
Step-by-step explanation:
I think you need a protractor to help you find the other angles to find x
Answer:
4 pounds of lime and 5 pounds of pears
Step-by-step explanation:
I + P = 9
0.5l + 1.5P = 9.5
I = 9 - P
0.5(9 - P) + 1.5P = 9.5
4.5-0.5P + 1.5P = 9.5
4.5 + P (1P) = 9.5
P = 9.5-4.5 = 5
I = 9 - 5 = 4
Answer: 4 pounds of lime and 5 pounds of pears
9514 1404 393
Answer:
20.3
Step-by-step explanation:
The distance formula can be used to find the side lengths.
d = √((x2 -x1)^2 +(y2 -y1)^2)
For the first two points, ...
d = √((3 -(-2))^2 +(6 -3)^2) = √(5^2 +3^2) = √34 ≈ 5.83
For the next two points, ...
d = √((2 -3)^2 +(-2-6)^2) = √(1 +64) = √65 ≈ 8.06
For the last and first points, ...
d = √((-2-2)^2 +(3-(-2)^2) = √(16 +25) = √41 ≈ 6.40
Then the sum of the side lengths is ...
5.83 +8.06 +6.40 = 20.29 ≈ 20.3
The perimeter of the triangle is about 20.3 units.
There are 8008 groups in total, in other to drive the children
<h3>How to determine the number of groups?</h3>
From the question, we have
- Total number of children, n = 16
- Numbers to children at once, r = 6
The number of group of children that could be carried at once is calculated using the following combination formula
Total = ⁿCᵣ
Where
n = 16 and r = 6
Substitute the known values in the above equation
Total = ¹⁶C₆
Apply the combination formula
ⁿCᵣ = n!/(n - r)!r!
So, we have
Total = 16!/10!6!
Evaluate
Total = 8008
Hence, the number of groups is 8008
Read more about combination at
brainly.com/question/11732255
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