Which statement about polygon PQRST and its image after dilation, polygon P'Q'R'S'T', is correct?

Mathematics

1 answer:

solniwko [45]3 years ago

6 0

Answer:

The length of diagonal PS and diagonal P'S' are in the ratio 1:3.

Step-by-step explanation:

Comparing the coordinates of the vertices,

P(0, -3)→P'(0, -9); Q(3, -2)→Q'(9, -6); R(3, 1)→R'(9, 3); S(0, 2)→S'(0, 6); T(-2, 0)→T'(-6, 0)

We can see that the pre-image points have been multiplied by a scale factor of 3. This means comparing the pre-image sides to the image sides, the ratio is 1:3. However, we must compare corresponding sides; the only choice comparing corresponding sides with a ratio of 1:3 is PS to P'S'.

You might be interested in

If the number of bacteria in a colony doubles every 25 hours and there is currently a population of 10,000 bacteria, what will t

MA_775_DIABLO [31]

Answer:

The population of 75 hours from now would be 40,000.

Step-by-step explanation:

The reason for this is because your initial number is 10,000 and when 25 hours pass by, your population would be 20,000. Another 25 hours pass by, and then your population would be 40,000. If you multiply 25 by 3, you will notice 75 hours have just passed, so your answer would be 40,000.

5 0

4 years ago

Nine less than four times a number equals fifteen

OverLord2011 [107]

4n-9=15. N=6 (n stands for number)

8 0

4 years ago

Read 2 more answers

The cashier service time at the local branch of the Rivertown bank has an exponential distribution with a mean of 2.5 minutes. W

aleksandrvk [35]

Answer: d. .2474.

Step-by-step explanation:

Given : The cashier service time at the local branch of the Rivertown bank has an exponential distribution with a mean of 2.5 minutes.

The cumulative distribution function for exponential distribution is :-

$P(X\leq x)= 1-e^{-\frac{x}{\lambda}}$

, where $\lambda$ = Mean of the distribution.

The probability that the service time is between 2 and 4 minutes will be :

$P(2\leq X \leq 4)=P(X\leq4)-P(X\leq 2)\\\\= (1-e^{\frac{-4}{2.5}})-(1-e^{\frac{-2}{2.5}})\\\\=e^{\frac{-2}{2.5}}-e^{\frac{-4}{2.5}}\\\\=0.449328964117-0.201896517995\\\\=0.247432446123\approx0.2474$