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3 years ago

What is the relationship between electric and magnetic fields?

2 answers:

4 0

Are there any answer choices but if its not this is the best answer i can give you, The magnetic field will be perpendicular to the electric field and vice versa An electric field is the area which surrounds an electric charge within which it is capable of exerting a perceptible force on another electric charge. A magnetic field is the area of force surrounding a magnetic pole, or a current flowing through a conductor, in which there is a magnetic flux. A magnetic field can be produced when an electric current is passed through an electric circuit wound in a helix or solenoid. The relationship that exists between an electric field and a magnetic field is one of electromagnetic interaction as a consequence of associating elementary particles. The electrostatic force between charged particles is an example of this relationship.

geniusboy [140]3 years ago

3 0

Moving point charges, such as electrons, produce complicated but well known magnetic fields that depend on the charge, velocity, and acceleration of the particles. Magnetic field lines form in concentric circles around a cylindrical current-carrying conductor, such as a length of

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A tank contains gas at 13.0°C pressurized to 10.0 atm. The temperature of the gas is increased to 95.0°C, and half the gas is re

fomenos

Answer:

The pressure of the remaining gas in the tank is 6.4 atm.

Explanation:

Given that,

Temperature T = 13+273=286 K

Pressure = 10.0 atm

We need to calculate the pressure of the remaining gas

Using equation of ideal gas

$PV=nRT$

For a gas

$P_{1}V_{1}=nRT_{1}$

Where, P = pressure

V = volume

T = temperature

Put the value in the equation

$10\times V=nR\times286$ ....(I)

When the temperature of the gas is increased

Then,

$P_{2}V_{2}=\dfrac{n}{2}RT_{2}$ ....(II)

Divided equation (I) by equation (II)

$\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}$

$\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}$

$P_{2}=\dfrac{10\times368}{2\times286}$

$P_{2}= 6.433\ atm$

$P_{2}=6.4\ atm$

Hence, The pressure of the remaining gas in the tank is 6.4 atm.

4 0

3 years ago

A wave transfers: Water particles energy matter

SashulF [63]

Answer:

Particles in a water wave exchange kinetic energy for potential energy. When particles in water become part of a wave, they start to move up or down. This means that kinetic energy (energy of movement) has been transferred to them

Explanation:

hope this helps u ....

pls mark this as the brainliest...

6 0

3 years ago

Magnitude of the normal force exerted by en in the figure below. What is the

vekshin1

Answer:

Explanation:

Reason is that the suitcase is exerted downward and when it moves downward the equation is mgsin tita

6 0

3 years ago

The movement of the tectonic plates is caused by?

Sveta_85 [38]

The movement of the tectonic plates is caused by convection currents in Earth´s mantle.

Answer: A) convection currents in Earth´s mantle.

7 0

3 years ago

Read 2 more answers

41. Planet Ayanna has a radius of 6.2 X 10%m and orbits the star named Dayli in 98 days. A new neighboring planet Clayton J-21 h

romanna [79]

Answer:

138.3 days

Explanation:

Given that a Planet Ayanna has a radius of 6.2 X 10%m and orbits the star named Dayli in 98 days. A new neighboring planet Clayton J-21 has been discovered and has a radius of 7.8 X 10 meters.

The period of time for Clayton J-21 to orbit Dayli can be calculated by using Kepler law.

T^2 is proportional to r^3

That is,

T^2/r^3 = constant

98^2 / 62^3 = T^2 / 78^3

Make T^2 the subject of formula.

T^2 = 98^2 / 62^3 × 78^3

T^2 = 19123.2

T = sqrt ( 19123.2 )

T = 138.2867 days

Therefore, the period of time for Clayton J-21 to orbit Dayli is 138.3 days approximately.

4 0

3 years ago