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3 years ago

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In order to protect underground pipelines and storage tanks made of iron, the iron is made the cathode of a voltaic cell through

a process called ___________________.sacrificial anodizationcathodic protectionrustinggalvanization

1 answer:

emmasim [6.3K]3 years ago

3 0

The answer would be that the process to protect the underground pipelines and storage tanks is cathodic protection.

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a charge of 7.2x10^-5C is placed in an Electric field with a strength of 4.8x10^5N/C. if the Electric potential energy of the ch

Alecsey [184]

Answer:

$d= 2.2 m$

Explanation:

The data given in the question is

Charge : q = $7.2 \times 10^{-5} C$

Electric field Strength : E = $4.8 \times 10^{5} N/C$

Electrical potential Energy : U = $75J$

Let, the distance be "d"

So, the formula for Electrical potential energy is

$U= q \times E \times d$

Simplified formula for distance become

$d=\frac{U}{q \times E}$

Now , insert the value

$d=\frac{75 J}{7.2 \times 10^{-5}C \times 4.8 \times 10^5 N/C}$

or,

$d=2.17 m$

Rounding off

$d= 2.2 m$

3 0

3 years ago

Based on the information in the table shown, which statement describes what a chemist would find if she analyzed a large piece o

Otrada [13]

A) It would likely contain all the isotopes of nickel shown in the chart in the same proportions.

[only one answer here, everything is wrong other than this ]

Hope this helps!

4 0

3 years ago

Read 2 more answers

Find time when boy catches the girl or when they are at their closest separation..

soldier1979 [14.2K]

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\implies{Time=10\:sec\:and\:30\:sec}}} \\\\$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}} \\ \\$

$\green{\underline{\bold{Given :}}} \\ \\ \:\:\:\: \bullet\:\:\tt\red{ Velocity \: of \: boy = 50 \: m/s} \\ \\ \:\:\:\: \bullet\:\: \tt\orange{Velocity \: of \: girl = 30 \: m/s }\\ \\ \:\:\:\: \bullet\:\:\tt\green{ Acceleration \: of \: boy = {1 \: m/s}^{2}} \\ \\ \:\:\:\:\bullet\:\: \tt\blue{Acceleration \: of \:girl= {2\: m/s}^{2} }\\ \\ \:\:\:\: \bullet \:\:\tt\purple{Sepration \: between \: them = 150 \: m }\\ \\ \\ \red{\underline{\bold{To \: Find :}}} \\ \\ \:\:\:\: \bullet\:\: \tt\blue{Time \: taken \: to \: catch \: the \: girl }\\$

<u>According to given question</u> :

$\\ \green{\star} \: \text{Using \: relative \: motion \: method} \\ \\ \green{ \circ} \: \tt Net \: velocity = 50 - 30 = 20 \: m/s \\ \\ \green{ \circ} \: \tt Net \: acceleration = 1 - 2 = - 1\: m /{s}^{2} \\\\ \\ \star\:\bold\red{\underline{\:As \: we \: know \: that\:}} \\\\ \tt\purple{: \implies s = ut + \frac{1}{2} {at}^{2}} \\ \\ \tt\green{: \implies 150 = 20 \times t + \frac{1}{2} \times -1 \times {t}^{2}} \\ \\ \tt\purple{: \implies 300 = 40t - {t}^{2}} \\ \\ \tt\green{: \implies {t}^{2} - 40t + 300 = 0} \\ \\ \tt\purple{: \implies t = \frac{ - ( - 40) \pm\sqrt{ { (- 40)}^{2} - 4 \times 1 \times 300} }{2 \times 1} }\\ \\ \tt\green{: \implies t = \frac{40 \pm \sqrt{1600 - 1200} }{2} }\\ \\ \tt\purple{: \implies t = \frac{40 \pm 20}{2} }\\ \\ \green{\tt: \implies t = 10 \: sec \: and \: 30 \: sec}$

7 0

3 years ago

How do I solve for angles 1-5?

pychu [463]

Keep in mind that the angles of a triangle add up to 180°. The total angle measurement of a line segment is also 180°. The total angle measurement of a right angle is 90°.

Look at the bottom side of the rectangle. It intersects with two lines to form 3 angles: a 70° angle and two angles θ₁

Take the sum of the three angles and set the sum equal to 180°, then solve for θ₁:

2θ₁ + 70° = 180°

2θ₁ = 110°

θ₁ = 55°

We have two right triangles inscribed in the rectangle. Let's focus on the triangle on the right side. It consists of the angles θ₁, θ₃, and a right angle. Take the sum of the three angles and set the sum equal to 180° then solve for θ₃:

θ₁ + θ₃ + 90° = 180°

55° + θ₃ + 90° = 180°

θ₃ = 35°

The triangle on the left side is just the mirror image of the triangle on the right side. These triangles have the same angle measurements, so we can say right away that θ₄ = 35°

Angles θ₂ & θ₃ and θ₄ & θ₅ make up right angles, which have a total angle measurement of 90°. θ₃ = θ₄ = 35°, therefore we can say that θ₂ = θ₅ = 90° - 35°

θ₂ = θ₅ = 55°

3 0

4 years ago

Thanks + BRAINLIST <br><br> Need correct answer ASAP

aliina [53]

Answer:

The options are not shown, so it is kinda hard to give you the exact answer.

But i can try to give a general explanation on the topic.

Interference happens when two waves interact between them. We usually use waves with the same wavelength and same phase.

There are two "main" types of interference:

Destructive interference: Happens when the peak of one wave and the trough of the other wave happen in the same place, then when we add these waves, we have a subtraction, and then the amplitude of the resultant wave is smaller than the amplitudes of the original waves (if both initial waves have the same amplitude, then the amplitude of the resultant wave in that position is zero).

Constructive interference: Similar to the previous case, but now the two waves have the peaks or toughs in the same position, then when we add the waves, we have an addition in the amplitude, then the amplitude of the resultant wave will be larger than the amplitudes of the initial waves.

Then if you are looking for constructive interference, you need to look for an option where the peaks of the waves coincide. For example, in the top image we can see, at the top, a wave with an amplitude of 2 units.

And at the bottom a wave with an amplitude of 1 unit.

We also can see that the peaks (and the tough) are in the same place, then we will have constructive interference. Then the amplitude of the resultant wave will be equal to the sum of the amplitudes of the initial waves (2 and 1)

Then the amplitude of the resultant wave is 2 units + 1 unit = 3 units.

5 0

3 years ago