Answer:
his speeds while going to city is 10 mph and while his round trip the speed will be 9 mph
Explanation:
Let say the speed of the bicycle while he moves towards the city is "v"
now the speed of the round trip must be smaller by 1 mph
so its speed for round trip will be

now we know that total time of the motion is 19 hr
so we will have


so we will have




by solving above equation we have

so his speeds while going to city is 10 mph and while his round trip the speed will be 9 mph
Answer:
the weight of the object decreases when it is taken from the Earth to the Moon
Explanation:
The weight of an object is defined as the product of the mass of the object with the acceleration due to gravity of the Planet.

where,
W = weight of the object
m = mass of the object
g = acceleration due to gravity on the planet
The mass of an object remains constant everywhere in the universe. Therefore, the weight is directly proportional to the value of acceleration due to gravity.
The value of acceleration due to gravity on the Moon is lesser than its value on the Earth.
<u>Hence, the weight of the object decreases when it is taken from the Earth to the Moon </u>
Answer:
Explanation:
Given:
U1 = 1.6 m/s
U2 = -1.1 m/s
M1 = 1850 kg
M2 = 1400 kg
V1 = 0.27 m/s
Using momentum- collision equation,
M1U1 + M2U2 = M1V1 + M2V2
1850 × 1.6 - 1400 × 1.1 = 1850 × 0.27 + 1400 × V2
1420 = 499.5 + 1400V2
V2 = 0.6575 m/s
B.
KE = 1/2 × MV^2
KEa1 + KEa2 = KEb1 + KEb2
Delta KE = KE2 - KE1
KEa1 = 2368 J
KEb1 = 847 J
KEa2 = 67.433 J
KEb2 = 302.6 J
KE1 = KEa1 + KEb1
= 3215 J
KE2 = 370.033 J
Delta KE = -2845 J.
Answer:
15 and 11 ohms
Explanation:
First one = For the parallel resistors 1 / (1/6 + 1/6 + 1/6) = 1/ (3/6 ) = 6/3 = 2 ohms then add the 3 and the 10 = 15 ohms
second one for the parallel portion equiv = (10+2)*24 / ( (10+2 + 24) = 8
then add the 3 in series = 11 ohms