Solve for y hdgkgsydkydutskgxtisit

Mathematics

2 answers:

Feliz [49]2 years ago

7 0

You said X = (5y+1) / (y-2)

Multiply each side by (y-2):

X(y-2) = (5y+1)

Eliminate parentheses:

Xy - 2X = 5y + 1

Add 2X to each side:

Xy = 5y + 1 + 2X

Subtract 5y from each side:

(X-5)y = 1 + 2X

Divide each side by (X-5):

iogann1982 [59]2 years ago

4 0

Answer:

$\large\boxed{y=\dfrac{2x+1}{x-5}}$

Step-by-step explanation:

$x=\dfrac{5y+1}{y-2}\\\\\dfrac{x}{1}=\dfrac{5y+1}{y-2}\qquad\text{cross multiply}\\\\(x)(y-2)=(1)(5y+1)\qquad\text{use the distributive property}\\\\xy-2x=5y+1\qquad\text{add 2x to both sides}\\\\xy=5y+2x+1\qquad\text{subtract 5y from both sides}\\\\xy-5y=2x+1\qquad\text{distributive}\\\\y(x-5)=2x+1\qquad\text{divide both sides by}\ (x-5)\\\\y=\dfrac{2x+1}{x-5}$

You might be interested in

Suppose you just purchased a digital music player and have put 15 tracks on it. After listening to them you decide that you like

Lilit [14]

The given case is an example of permutation problem because the order is important given that you should like the first two songs. The sample space is calculated through the equation,
15P2 = 210
Then, there are 3 songs that you liked, the probability of picking 2 out of them is,
3P2 = 6
Dividing the latter by the earlier result will give us an answer of 1/35.

8 0

2 years ago

20 POINTS!!!

notka56 [123]

$\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------$

$(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s$