Answer:
2 and a half, but it wants it as a mixed fraction which would be 5/2
Step-by-step explanation:
i hope this helped :)
Answer:
A. EG = √3 × FG
D. EG = √3/2 × EF
E. EF = 2 × FG
Step-by-step explanation:
∵ tan 60 = √3
∵ tan60 = EG/GF
∴ EG/GF = √3
∴ EG = √3 × GF ⇒ A
∵ m∠F = 60°
∵ sin60 = √3/2
∵ sin 60 = EG/EF
∴ √3/2 = EG/EF
∴ EG = √3/2 × EF ⇒ D
∵ cos60 = 1/2
∵ cos60 = GF/EF
∴ GF/EF = 1/2
∴ EF = 2 × GF ⇒ E
Area of a parallelogram=base x heigth
Data:
base=(2x+3)
heigth=(ax+5)
area of this parallelogram=8x²+bx+15
Therefore:
8x²+bx+15=(2x+3)(ax+5)
8x²+bx+15=2ax²+10x+3ax+15
8x²+bx+15=2ax²+(10+3a)x+15
Then:
8x²=2ax²
a=(8x²)/(2x²)=4
bx=(10+3(4))x
bx=(10+12)x
b=22x/x=22
Answer: a=4 and b=22.
Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
![\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%261%262%5C%5C1%26-2%263%5Cend%7Barray%7D%5Cright%5D)
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
or
[
,
,
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[
,
,
]
In conclusion, the two unit vectors are;
[
,
,
]
and
[
,
,
]
<em>Hope this helps!</em>
Answer:
Average rate of change 
Step-by-step explanation:
Given function is
and we need to find average rate of change of the function from
.
Average rate of change 
So,

Average rate of change

Hence, average rate of change of the function
over the intervel
is
.