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masha68 [24]
3 years ago
10

Please help I took a screenshot of the question

Mathematics
2 answers:
Ymorist [56]3 years ago
8 0
I don’t understand what the question is telling me
natulia [17]3 years ago
8 0

Answer:

\displaystyle \frac{\cos A}{\cos B}=1

Step-by-step explanation:

<u>Trigonometric Ratios</u>

The relations between the sides of a right triangle and the angles are called trigonometric ratios.

The longest side of the triangle is called the hypotenuse and the other two sides are the legs.

Selecting any of the acute angles as a reference, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides.

The cosine is defined as:

\displaystyle \cos\theta=\frac{\text{adjacent leg}}{\text{hypotenuse}}

Considering angle A, we have:

\displaystyle \cos A=\frac{3}{4.24}

Considering angle B:

\displaystyle \cos B=\frac{3}{4.24}

Both expressions are exactly the same, thus:

\displaystyle \frac{\cos A}{\cos B}=1

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tankabanditka [31]
1 inch is the same as 8/8
Use this to solve
8/8 - 3/8 = 5/8
The 1 inch button is 5/8 longer than the other button. Hope this helps!
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2 years ago
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I need help pzgsgddhdhddg
yan [13]

Answer:

The correct answer is 756÷10^2=7.56

Step-by-step explanation:

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3 0
3 years ago
cam hits the bullseye in 8 darts out of 15 throws. what is the experimental probability that came next throws will hit the bulls
Zigmanuir [339]

Answer:

A darts player practices throwing a dart at the bull’s eye on a dart board. Her probability of hitting the bull’s eye for each throw is 0.2.

(a) Find the probability that she is successful for the first time on the third throw:

The number F of unsuccessful throws till the first bull’s eye follows a geometric

distribution with probability of success q = 0.2 and probability of failure p = 0.8.

If the first bull’s eye is on the third throw, there must be two failures:

P(F = 2) = p

2

q = (0.8)2

(0.2) = 0.128.

(b) Find the probability that she will have at least three failures before her first

success.

We want the probability of F ≥ 3. This can be found in two ways:

P(F ≥ 3) = P(F = 3) + P(F = 4) + P(F = 5) + P(F = 6) + . . .

= p

3

q + p

4

q + p

5

q + p

6

q + . . . (geometric series with ratio p)

=

p

3

q

1 − p

=

(0.8)3

(0.2)

1 − 0.8

= (0.8)3 = 0.512.

Alternatively,

P(F ≥ 3) = 1 − (P(F = 0) + P(F = 1) + P(F = 2))

= 1 − (q + pq + p

2

q)

= 1 − (0.2)(1 + 0.8 + (0.8)2

)

= 1 − 0.488 = 0.512.

(c) How many throws on average will fail before she hits bull’s eye?

Since p = 0.8 and q = 0.2, the expected number of failures before the first success

is

E[F] = p

q

=

0.8

0.2

= 4.

7 0
3 years ago
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A tennis player makes a successful first serve 51% of the time. If she serves 9 times, what is the probability that she gets exa
aleksley [76]

Answer:

P(X=3)

And we can use the probability mas function and we got:

P(X=3)=(9C3)(0.51)^3 (1-0.51)^{9-3}=0.1542  

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=9, p=0.51)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And we can use the probability mas function and we got:

P(X=3)=(9C3)(0.51)^3 (1-0.51)^{9-3}=0.1542  

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3 years ago
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Alik [6]
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