Answer:
2x -8x+15=0
-6x+15=0
-6x= 15
x= 5/2
Step-by-step explanation:
Answer:
81 times the original size
Step-by-step explanation:
AA0ktA=3A0=?=?=25hours=A0ekt
Substitute the values in the formula.
3A0=A0ek⋅25
Solve for k. Divide each side by A0.
3A0A0=e25k
Take the natural log of each side.
ln3=lne25k
Use the power property.
ln3=25klne
Simplify.
ln3=25k
Divide each side by 25.
ln325=k
Approximate the answer.
k≈0.044
We use this rate of growth to predict the number of bacteria there will be in 100 hours.
AA0ktA=3A0=?=ln325=100hours=A0ekt
Substitute in the values.
A=A0eln325⋅100
Evaluate.
A=81A0
At this rate of growth, we can expect the population to be 81 times as large as the original population.
First, we need to figure out 10% of fifteen.
So, we multiple 15 by 10% (or 0.1 in simpler terms).
That gives us 1.5, which is our mark-up price.
So, finally we add the markup price to the original price to obtain the selling price.
1.5 + 15 = 16.5
The owner charges $16.50 for 1kg of sugar!
Answer:
A.
Step-by-step explanation:
It's the first one. The angles are supplementary not complementary.
Answer:

Step-by-step explanation:

Double negative = Positive:

Apply negative exponent formula:

Multiply:

Apply exponent rule: 
Thus, 
Simplify:
