You probably already know that the range of
is all non-negative real numbers, right?
I can't exactly graph it for you but I can tell you how it looks like :-)
So, your graph would have a positive slope that is 4/3. The y-intercept is below the x-axis at -1/3. From that point, the next point to the right would be (3, 11/3). Basically it would go up 4 and right 3 from your y-intercept. I hope this helps :-)
Answer:
D
Step-by-step explanation:
Using the sine ratio in the right triangle
sin B = 
= 
= 
, thus
B = 
( ) ≈ 12.84° → D
Answer:
5.04
Step-by-step explanation:
Answer:
B. y = tan x and C. y = cot x
Step-by-step explanation:
Range:
range is defined as the set of values that any given function y=f(x), can take for which the x values are defined. It is the value that y can take for the values of x.
Given:
From the given options
the range of tanx and cotx are all real numbers
as the period of tanx and cotx are π
where as range of secx is all real numbers except π/2 + n*π i.e.
(-∞ , -1] U [1 , + ∞)
And range of cscx is all real numbers except n*π i.e.
(-∞ , -1] U [1 , + ∞)
So from the given option:
option B and C are correct while A and D are not !
