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guapka [62]
4 years ago
11

Century is to decade as dollar is to penny,nickel,dime,quarter

Mathematics
1 answer:
son4ous [18]4 years ago
6 0
Century= 10 decades a decade is ten years. A dollar=10 dimes a dime is ten cents. ANSWER: DIME
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During a promotional event a sporting goods store gave a free t-shrit to every 10 customer and a free water bottle to every 15 c
SVETLANKA909090 [29]

9514 1404 393

Answer:

  30th

Step-by-step explanation:

The least common multiple of 10 and 15 is 30.

  30 = 10×3 = 15×2

The 30th customer will be the first to receive both promotional items.

3 0
3 years ago
Which best explains why all equilateral triangles are similar?
Neko [114]

Answer:

D

Step-by-step explanation:

I hope this helps you out!

7 0
2 years ago
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The fountain is made up of two semicircles and a quarter circle. Find the perimeter and the area of the fountain. Round the peri
Andrej [43]
FOUND THE COMPLETE QUESTION IN ANOTHER SOURCE.ATTACHED IMAGE.
 For this case what we have is the following:
 For the two semicircles we can model it as a complete circle.
 We have to then:
 
 Perimeter: 
 P = 2 * pi * r
 or
 P = pi * d
 Where,
 r = radius
 d = diameter
 Therefore the perimeter is:
 P = 10 * pi
 For the largest circle we have:
 radius = 10
 Perimeter:
 P '= 2pi10
 P '= 20pi
 1/4 since 1/4 circle:
 P '' = 20pi / 4 = 5pi
 Then, the total perimeter of the source is:
 Pt = P + P '' = 10pi + 5pi = 15pi
 Pt = 15 * (3.141592)
 Pt = 47.1239
 round
 Pt = 47.1 ft

 Area:
 The total area will be:
 A = A (two semicircles) + A (quarter big circle)
 A = (pi / 4) * (d ^ 2) + (1/4) * pi * r ^ 2
 A = (pi / 4) * ((10) ^ 2) + (1/4) * pi * (5) ^ 2
 A = 98.17477042 feet ^ 2
 Round:
 A = 98.2 feet ^ 2

 Answer: 
 Perimeter of the source: 
 Pt = 47.1 ft 
 Area of the source: 
 A = 98.2 feet ^ 2

5 0
3 years ago
I will mark brainliest
matrenka [14]
A: 2,5
B: 3,1
C: -2,4



Explanation:


When you’re moving right and up you would add however many numbers you moved up to the original points because going right on a graph makes the X a larger number, and going up makes it larger.
5 0
3 years ago
Match each function with the corresponding function formula when h(x)=5-3x and g(x)=-3+5
Grace [21]

Answer:

k(x) = (3g + 5h)(x) ⇒ (1)

k(x) = (5h - 3g)(x) ⇒ (3)

k(x) = (h - g)(x) ⇒ (2)

k(x) = (g + h)(x) ⇒ (4)

k(x) = (5g + 3h)(x) ⇒ (5)

k(x) = (3h - 5g)(x) ⇒ (6)

Step-by-step explanation:

* To solve this problem we will substitute h(x) and g(x) in k(x) in the

  right column to find the corresponding function formula in the

  left column

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

- Lets start with the right column

# k(x) = (3g + 5h)(x)

∵ g(x) = -3^x + 5

∵ 3g(x) = 3[-3^x + 5] = [3 × -3^x + 3 × 5]

- Lets simplify 3 × -3^x

 take the negative out -(3 × 3^x), and use the rule a^n × a^m = a^(n+m)

∴ -3(3 × 3^x) = -(3^x+1)

∴ 3g(x) = -3^x+1 + 15

∵ h(x) = 5 - 3x

∵ 5h(x) = 5[5 - 3x] = [5 × 5 - 5 × 3x] = 25 - 15x

- Now substitute 3g(x) and 5h(x) in k(x)

∵ k(x) = (3g + 5h)(x)

∴ k(x) = -3^x+1 + 15 + 25 - 15x ⇒ simplify

∴ k(x) = 40 - 3^x+1 - 15x

∴ k(x) = 40 - 3^x+1 - 15x ⇒ k(x) = (3g + 5h)(x)

* k(x) = (3g + 5h)(x) ⇒ (1)

# k(x) = (5h - 3g)(x)

∵ 5h(x) = 25 - 15x

∵ 3g(x) = -3^x+1 + 15

∵ k(x) = (5h - 3g)(x)

∴ k(x) = 25 - 15x - (-3^x+1 + 15) = 25 -15x + 3^x+1 - 15 ⇒ simplify

∴ k(x) = 10 + 3^x+1 - 15x

∴ k(x) = 10 + 3^x+1 - 15x ⇒ k(x) = (5h - 3g)(x)

* k(x) = (5h - 3g)(x) ⇒ (3)

# k(x) = (h - g)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (h - g)(x)

∴ k(x) = 5 - 3x - (-3^x + 5) = 5 - 3x + 3^x - 5 ⇒ simplify

∴ k(x) = 3^x - 3x

∴ k(x)= 3^x - 3x ⇒ k(x) = (h - g)(x)

* k(x) = (h - g)(x) ⇒ (2)

# k(x) = (g + h)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (g + h)(x)

∴ k(x) = -3^x + 5 + 5 - 3x ⇒ simplify

∴ k(x) = 10 - 3^x - 3x

∴ k(x)= 10 - 3^x - 3x ⇒ k(x) = (g + h)(x)

* k(x) = (g + h)(x) ⇒ (4)

# k(x) = (5g + 3h)(x)

∵ g(x) = -3^x + 5

∵ 5g(x) = 5[-3^x + 5] = [5 × -3^x + 5 × 5] = 5(-3^x) + 25

∴ 5g(x) = -5(3^x) + 25

∵ h(x) = 5 - 3x

∵ 3h(x) = 3[5 - 3x] = [3 × 5 - 3 × 3x] = 15 - 9x

- Now substitute 5g(x) and 3h(x) in k(x)

∵ k(x) = (5g + 3h)(x)

∴ k(x) = -5(3^x) + 25 + 15 - 9x ⇒ simplify

∴ k(x) = 40 - 5(3^x) - 9x

∴ k(x) = 40 - 5(3^x) - 9x ⇒ k(x) = (5g + 3h)(x)

* k(x) = (5g + 3h)(x) ⇒ (5)

# k(x) = (3h - 5g)(x)

∵ 3h(x) = 15 - 9x

∵ 5g(x) = -5(3^x) + 25

∵ k(x) = (3h - 5g)(x)

∴ k(x) = 15 - 9x - [-5(3^x) + 25] = 15 - 9x + 5(3^x) - 25 ⇒ simplify

∴ k(x) = 5(3^x) - 9x - 10

∴ k(x) = 5(3^x) - 9x - 10 ⇒ k(x) = (3h - 5g)(x)

* k(x) = (3h - 5g)(x) ⇒ (6)

4 0
3 years ago
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