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Bingel [31]
3 years ago
6

Help ASAP please ! Please explain

Mathematics
1 answer:
Anni [7]3 years ago
3 0
I don’t know i never seen this math problem before
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A toy company has determined that the revenue generated by a particular toy is modeled by the following equation:
Artemon [7]
R(x) = 11x - 0.025x^2
Revenue is maximum when dr(x)/dx = 0
dr(x)/dx = 11 - 0.05x = 0
0.05x = 11
x = 11/0.05 = 220
The revenue will be maximum when 220000 toys are produced.

r(220) = 11(220) - 0.025(220)^2 = 2,420 - 1,210 = 1,210
Therefore, maximum revenue = $1210000
8 0
3 years ago
Please answer need help ASAP
9966 [12]

Correct answer is 8. I hope I helped(:

6 0
3 years ago
Which expression is equivalent to (5x–3y4)2?
bogdanovich [222]
4 because it is b I looked we will get it done together
8 0
3 years ago
a pole that is 3.3 M tall casts a shadow that is 1.22 M long at the same time a nearby Tower cast a shadow that is 50.75 M long
jenyasd209 [6]
Since there is no distance between the pole and the base of the tower, we can assume that the pole is at the base of the tower. 
We can create a right triangles between the pole and its shadow and between the tower and its shadow as shown in the figure. Let x be the height of the tower. Since our triangles are similar the ratio between its sides is going to be proportional, so we can establish a proportion to find x:
\frac{x}{3.3} = \frac{50.75}{1.22}
x= \frac{(50.75)(3.3)}{1.22}
x=137.27

We can conclude that the tower is 137.27 meters tall.

6 0
3 years ago
Read 2 more answers
Find the area of a 2-inch-wide decorative border around a rectangular canvas painting, where L is the length and W is the width
lions [1.4K]

Answer:

  4L +4W +16 square inches

Step-by-step explanation:

The area of the border is the equivalent of that of a rectangle with a width equal to the width of the border, and a length equal to the length of the midline of the border. That length is the perimeter of the rectangle that is L+2 units long and W+2 units wide.

  border midline length = 2((L+2) +(W+2)) = 2L +2W +8

Then the border area is ...

  border area = (border width)(border length) = (2)(2L +2W +8)

  border area = 4L +4W +16 . . . square inches

_____

You can also figure this as the difference between the area of the rectangle with the border and the area of the rectangle inside the border:

  border area = total area - canvas area

  = (L+4)(W+4) -LW = LW +4L +4W +16 -LW

  = 4L +4W +16 . . . . square inches

4 0
3 years ago
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