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Vikki [24]
3 years ago
6

The speed of the current in a river is 6mph. A ferry operator who works that part of the river is looking to buy a new boat for

her business. Every day, her route takes her 22.5 miles each way against the current and back to her dock, and she needs to make the trip in a total of 9 hours. She has a boat in mind, but she can only test it on a lake where there is no current at all. How fast must the boat go on the lake in order for it to serve the ferry operator's needs?

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
4 0
Hello,
Please, see the attached files.
Thanks.

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6. You begin work at 8:30 am. You take an unpaid lunch break from 11:45 am to 12:30 pm
STALIN [3.7K]

Answer:

7 hours 15 minutes

7.25 hours

Step-by-step explanation:

Break from 11:45 am to 12:30 pm = 45 minutes

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Total break hours = 45 minutes + 30 minutes

= 1 hour 15 minutes

Total work day hours from 8:30 am to 5:00 pm = 8 hours 30 minutes

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= 8 hours 30 minutes - 1 hour 15 minutes

= 7 hours 15 minutes

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7 0
3 years ago
Can someone help me and explain? I will mark brainlest. ♡
Sedbober [7]

Answer:

p'(4) = -3

q'(8) = \frac{1}{4}\\

Step-by-step explanation:

For p'(4):

p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)

p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3

For q'(8):

q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}

q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}

4 0
3 years ago
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