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Aleks04 [339]
3 years ago
14

AMA is N years old now.How old will she be in 10 years?

Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

N+10

Step-by-step explanation:

current age N, shebwill get 10 years older

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Each data point represents a single white dwarf supernova that has been observed. the data points that appear farthest to the le
MakcuM [25]
A type Ia supernova is a type of supernova that occurs in binary systems (two stars orbiting one another) in which one of the stars is a white dwarf. The other star can be anything from a giant star to an even smaller white dwarf<span>.

I hope my answer has come to your help. God bless and have a nice day ahead!
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6 0
3 years ago
Point A(3,8)
alexandr402 [8]

Answer:

\displaystyle d = \sqrt{65}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point A(3, 8)

Point B(-1, 1)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(-1 - 3)^2 + (1 - 8)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{(-4)^2 + (-7)^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{16 + 49}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{65}
5 0
3 years ago
The sum of three consecutive odd integers is 207. What are the​ integers?
nikdorinn [45]
Hey!

It says that it is the sum of 3 consecutive odd integers right?

So then we give these numbers some variables to work with like so...

x = 1st number
x + 2 = 2nd number
x + 4 = 3rd number

now set all of them equal to 207

x + x + 2 + x + 4 = 207
3x + 6 = 207
3x = 201
<u>x = 67</u><u />                     <u>x + 2 = 69</u><u />              <u /><u />   <u>x + 4 = 71
</u>
<u>
</u>


4 0
3 years ago
(6z 2 - 4z + 1)(8 - 3z).
Yakvenalex [24]
Distributive property
a(b+c)+ab+ac
a(b-c)=ab-ac

(6z^2-4z+1)(8-3z)
move for nicety
(8-3z)(6z^2-4z+1)
distribute
8(6z^2-4z+1)-3z(6z^2-4z+1)=
48z^2-32z+8-18z^3+12z^2-3z=
-18z^3+48z^2+12z^2-32z-3z+8=
-18z^3+60z-35z+8
7 0
4 years ago
Solve 5x + 14 = k for x.
Y_Kistochka [10]

Answer:

x = (k-14)/5

Step-by-step explanation:

5x + 14 = k

Subtract 14 from each side

5x + 14-14 = k-14

5x = k-14

Divide by 5

5x/5 = (k-14)/5

x = (k-14)/5

4 0
3 years ago
Read 2 more answers
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