A type Ia supernova is a type of supernova that occurs in binary systems (two stars orbiting one another) in which one of the stars is a white dwarf. The other star can be anything from a giant star to an even smaller white dwarf<span>.
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Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
Point A(3, 8)
Point B(-1, 1)
<u>Step 2: Find distance </u><em><u>d</u></em>
- Substitute in points [Distance Formula]:

- [√Radical] (Parenthesis) Subtract:

- [√Radical] Evaluate exponents:

- [√Radical] Add:

Hey!
It says that it is the sum of 3 consecutive odd integers right?
So then we give these numbers some variables to work with like so...
x = 1st number
x + 2 = 2nd number
x + 4 = 3rd number
now set all of them equal to 207
x + x + 2 + x + 4 = 207
3x + 6 = 207
3x = 201
<u>x = 67</u><u /> <u>x + 2 = 69</u><u /> <u /><u /> <u>x + 4 = 71
</u><u>
</u>
Distributive property
a(b+c)+ab+ac
a(b-c)=ab-ac
(6z^2-4z+1)(8-3z)
move for nicety
(8-3z)(6z^2-4z+1)
distribute
8(6z^2-4z+1)-3z(6z^2-4z+1)=
48z^2-32z+8-18z^3+12z^2-3z=
-18z^3+48z^2+12z^2-32z-3z+8=
-18z^3+60z-35z+8
Answer:
x = (k-14)/5
Step-by-step explanation:
5x + 14 = k
Subtract 14 from each side
5x + 14-14 = k-14
5x = k-14
Divide by 5
5x/5 = (k-14)/5
x = (k-14)/5