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Alina [70]
3 years ago
8

The sum of nine and twice a number is 5353. find the number.

Mathematics
1 answer:
Nadya [2.5K]3 years ago
6 0
Equation: 9+2x=5,353
               -9        -    9
                     2x=5,344
then divide both sides by 2 

                    x=2,672
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The length of line PQ is 7.5 inches. what is the absolute error of the measurement?
Rashid [163]

Answer:

The absolute error of the measurement is 0.25 inches

Step-by-step explanation:

we know that

The absolute error of a measurement is equal to one  half the unit of measure.

In this problem we have

7.5 inches

The measurement is given  by 0.5 inches

So

the absolute error of this  measurement is  

\frac{1}{2}(0.5)=0.25\ in

Therefore

the exact measurement could be between  

7.5 (+/-) 0.25 in

That is, between  7.25 in and  7.75 in

4 0
3 years ago
GIVING BRAINLY TO CORRECT answer
crimeas [40]

Answer:

False

Step-by-step explanation:

Range is defined as the greatest possible number minus the lowest possible number. The highest is 150 (in thousands) and the lowest is 25, meaning the range would be 125,000 and not 150,000.

Hope this helps!

8 0
2 years ago
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Complete the square <br> x^2+4-12=0
Tatiana [17]

Answer:

x = -6

x = 2

Step-by-step explanation:

x² + 4 - 12 = 0

= (x + 6)(x - 2)

x + 6 = 0

x = -6

x - 2 = 0

x = 2

5 0
3 years ago
Some researchers have conjectured that stem-pitting disease in peach-tree seedlings might be controlled with weed and soil treat
stiks02 [169]

Answer:

Part A

b. 14.6 ± 7.38

Part B

b. 3.43

Part C

a. P-value < 0.01

Part D

b. There is sufficient evidence to reject the null hypothesis

Step-by-step explanation:

Part A

The given data are;

The number of seedlings in the field = 20

The number of seedlings selected to receive herbicide A = 10

The number of seedlings selected to receive herbicide B = 10

The height in centimeters of seedlings treated with Herbicide A, \overline x _1 = 94.5 cm

The standard deviation, s₁ = 10 cm

The height in centimeters of seedlings treated with Herbicide B, \overline x _2 = 109.1 cm

The standard deviation, s₂ = 9 cm

The 90% confidence interval for μ₂ - μ₁, is given as follows;

\left (\bar{x}_{2}- \bar{x}_{1}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

The critical-t at 95% and n₁ + n₂ - 2 degrees of freedom is given as follows;

The degrees of freedom, df = n₁ + n₂ - 2 = 10 + 10 - 2 = 18

α = 100% - 90% = 10%

∴ For two tailed test, we have, α/2 = 10%/2 = 5% = 0.05

t_{(0.025, \, 18)} = 1.734

C.I. = \left (109.1- 94.5 \right )\pm 1.734 \times \sqrt{\dfrac{10^{2}}{10}+\dfrac{9^{2}}{10}}

C.I. ≈ 14.6 ± 7.37714603353

The 90% C.I. ≈ 14.6 ± 7.38

b. 14.6 ± 7.38

Part B

With the hypotheses are given as follows;

H₀; μ₂ - μ₁ = 0

Hₐ; μ₂ - μ₁ ≠ 0

The two sample t-statistic is given as follows;

t=\dfrac{(\bar{x}_{2}-\bar{x}_{1})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}+\dfrac{s _{2}^{2}}{n_{2}}}}

t-statistic=\dfrac{(109.1-94.5)}{\sqrt{\dfrac{10^{2} }{10}+\dfrac{9^{2}}{10}}} \approx 3.43173361147

The two sample t-statistic ≈ 3.43

b. 3.43

Part C

From the t-table, the p-value, we have, the p-value < 0.01

a. P-value < 0.01

Part D

Given that a significance level of 0.05 level is used and the p-value of 0.01 is less than the significance level, there is enough statistical evidence to reject the null hypothesis

b. There is sufficient evidence to reject the null hypothesis.

4 0
3 years ago
What is the sum of (2x - 5y) and (x + y)?
seraphim [82]

Answer:

3x-4y

Step-by-step explanation:

combine like terms. 2x+x=3x.

-5y+y=-4y

6 0
3 years ago
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