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Ulleksa [173]
3 years ago
5

ticket to a broadway show cost $35 for adult and $15 for childern . the total receipts for 1,650 ticket at one performance were

$47,150. How many adult ticket and how many child ticket were sold?​

Mathematics
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

The number of adult ticket sold was 1,120 and the number of child ticket sold was 530

Step-by-step explanation:

Let

x ----> the number of adult ticket sold

y ----> the number of child ticket sold

we know that

x+y=1,650 ----> equation A

35x+15y=47,150 ----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (1,120,530)

see the attached figure

therefore

The number of adult ticket sold was 1,120 and the number of child ticket sold was 530

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marusya05 [52]

The number of cars that sold on the third week is (P3=26)

The number of cars that sold on the first week is (P4=33)

<u>Step-by-step explanation:</u>

<u>Given:</u>

  • The number of cars that sold on the first week is (P0=7)
  • The number of cars that sold on the second week is (P0=12)

We have to find the number of cars being sold on the upcoming week

From the data given above, frame the equation

Pn = Pn −1+7   ( 12-5=7  it denotes the cars sold in the first and the second  week)

Pn=5+7n (cars in the first week and the cars sold in the second week into "n" n is used to find the cars sold in the upcoming weeks)

(If n=3)

Pn=5+7(3)

Pn=26

The number of cars that sold on the third week is (P3=26)

(If n=4)

Pn=5+7(4)

Pn=33

The number of cars that sold on the first week is (P4=33)

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4 years ago
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Answer:

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or, 18x - 6x = 42+12

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