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mixas84 [53]
3 years ago
15

Please help me with the process to find the answer for #15, #16, #17 and #18

Mathematics
1 answer:
timama [110]3 years ago
8 0

Well I wanna do you want us to pick you guys up tomorrow at night to

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What is the output from the following machine when the input is 4
11Alexandr11 [23.1K]
Would it be -1? 4-7= -3 and -3/3 = -1
6 0
3 years ago
6x-2y=-2
tatiyna

Answer:

7x-7y=14

x=3 and y= 1

i think :)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the minimum value of F(x)= 10x^{2} -6x-3<br> 3/10 or -39/10
kolezko [41]

Answer: 3/10

Step-by-step explanation:

Take the derivative of 10x^2-6x-3 to get 20x-6. Set that equal to 0 to find the critical points of the function. The critical points is when the slope is either 0 or undefined.

Now do:

20x-6=0\\20x=6\\x=\frac{6}{20} = \frac{3}{10}

There are quite a few more steps to actually find the minimum, but for this example you can automatically assume its a minimum because it is the only critical point of the function. Ill show you these extra steps tho.

Plug in two numbers into the derivative. One that is less than 3/10 and one that is greater than 3/10. The numbers 0 and 1 are fine. When x = 0, the function is -6. When x = 1, the function is +14. A switch from negative to positive indicates a minimum value

6 0
3 years ago
Jody's older brother is only three years less than twice Jody's age. If the sum of their ages is 30, then what is the age of jod
swat32

Answer: 19

Step-by-step explanation:

j+2j-3 = 30

3j = 33

j = 11

and

b = 2j-3

b = 2(11)-3

b = 19

7 0
4 years ago
Read 2 more answers
Suppose it is known from large amounts of historical data that X, the number of cars that arrive at a specific intersection duri
Andrew [12]

Answer:

a) P(x>8) = 0.3937

b)  P(x = 2) =0.04661

Step-by-step explanation:

a) From to find the probabilty that in this specific time period, more than 8 cars arrive at the intesection, we use the probability function thus

P(x>8) = 1 - P(x≤8),  Cause you can use the complement for calculate this probability , then:

P(x≤8) = \frac{e^{-6}*6^{0} }{0!}+\frac{e^{-6}*6^{1} }{1!}+\frac{e^{-6}*6^{2} }{2!}+... , until x= 8, then you obtain:

P(x≤8)=0.6063 and

P(x>8) = 1 - P(x≤8)= 1-0.6063 = 0.3937

b) P(x=2)= \frac{e^{-6}*6^{2}  }{2!}

 P(x = 2) =0.04661

3 0
3 years ago
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