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djyliett [7]
3 years ago
9

How do you simplify this equations?

Mathematics
1 answer:
Akimi4 [234]3 years ago
8 0
The answer is:

Square root of 77
—————————
22

You need to rationalize the denominator meaning that you have to get rid of the square root signs in denominator

To get rationalize the denominator you need to multiply both sides by square root of 11

(Square root of 7)(square root of 11)
——————————————————
2(square root of 11)^2

When squaring a square root it makes the square root “go away”

(Square root of 77)
——————————
2(square root of 11^2 or 122) = 2(11)

So:

The answer is

square root of 77
—————————
22

~~hope this helps~~
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You must factor the equation by find what 2 numbers can multiply to equal -12 and add to equal 1.

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They y also must equal zero.

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Outcome
Luda [366]

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Step-by-step explanation:

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2 years ago
Use the Quadratic formula to find all real zeros of the 2nd degree polynomial
schepotkina [342]

Answer:

  x ∈ {-5, -1}

Step-by-step explanation:

Here's the solution using the quadratic formula:

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-24\pm\sqrt{24^2-4\cdot 4\cdot 20}}{2\cdot 4}\\\\=\dfrac{-24\pm\sqrt{576-320}}{8}=\dfrac{-24\pm\sqrt{256}}{8}\\\\=\dfrac{-24\pm 16}{8}=-3\pm 2=\{-5,-1\}

The real zeros are -5 and -1.

_____

There are many ways to check your answer. One of them is to look at the given quadratic, which has no changes of sign in its coefficients. (They are all positive.) That means there can be no positive real roots, so already you know that x=0.5 won't work.

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3 years ago
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