<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
Answer: 1ST ONE CUZ THE LINE IS AT A CERTAIN ANGLE AT A POINT TO MATCH THE FIRST ANSWER
Step-by-step explanation:
Step-by-step explanation:
a = 2
b = 1
c = 4
<h2>Question:</h2>
= Solution ,
= 3 × 2 × 4 - 2 + 2 × 1
= 24 - 2 + 2
= 24 + 2 - 2
= 26 - 2
= 24
hence the answer is 24....
Answer:
The domain is (-∞,∞)
Step-by-step explanation:
Since there's no limit to this function, the values are infinity.
