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murzikaleks [220]
3 years ago
10

Pat has a 10 cm length of string she's going to use to measure a small square table. The side length she measures is five strin

g. What are the dimensions of the table?
Mathematics
2 answers:
garri49 [273]3 years ago
6 0
If she uses 5 strings to measure 1 side, each side of the square is 50 cm long
Vesna [10]3 years ago
5 0
The table is 50cm by 50cm
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C

Step-by-step explanation:

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Each of the four angles of a quadrilateral measures 90°. How many rectangles can you construct using this condition?
skad [1K]
The defenition of a rectangle is that it has 4 angles that measure 90 degrees
ther are infinite legnths and inifinite numbers
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The formula for finding the perimeter of a rectangle is p= 2l 2w solve the formula for w.
I am Lyosha [343]

Answer:

w = \frac{p -2l}{2}

Step-by-step explanation:

p = 2l + 2w  Subtract 2l from both sides of the equation

p - 2l = 2p  Divide both sides by 2

\frac{p -2l}{2} = w

5 0
1 year ago
What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE
Nutka1998 [239]

Answer:

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),  \left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

Step-by-step explanation:

Let points D, E and F have coordinates (x_D,y_D),\ (x_E,y_E) and (x_F,y_F).

1. Midpoint M of segment DF has coordinates

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).

2. Midpoint N of segment EF has coordinates

\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0
3 years ago
Maria is installing gutters on her rectangular shed that measures 10 ft by 9 ft she has 23 ft of gutter already and need to purc
Paha777 [63]

Answer:

Maria needs 3 lengths of gutter of finish the shed.

Step-by-step explanation:

We need to calculate the perimeter of the rectangular shed to know how much  5 feet gutter is needed.

The perimeter of the shed is p = 2(l + b) where l = 10ft and b = 9 ft

p = 2(10 + 9) = 2(19) = 38 ft

Now, the perimeter of the shed also equal 23 ft of gutter already installed plus 5x ft gutter where x = number of gutters.

So 23 + 5x = 38

collecting like terms, we have

5x = 38 - 23

5x = 15

dividing through by 5 we have

5x/5 = 15/5

x = 15/5

x = 3

So, Maria needs 3 lengths of gutter of finish the shed.

8 0
3 years ago
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