All categories

3 years ago

What is the justification for each step in solving the inequality?

Mathematics

1 answer:

Fed [463]3 years ago

5 0

Step-by-step explanation:

$3x+\frac{5}{8}\geq 4x-\frac{1}{2}$

Subtract 5/8 on both sides

To subtract 5/8 we make the denominators same

$3x\geq 4x-\frac{1*4}{2*4}-\frac{5}{8}$

Addition or Subtraction property of order is used

$3x\geq 4x-\frac{9}{8}$

Subtract 4x on both sides

Addition or Subtraction property of order is used

$-x\geq -\frac{9}{8}$

Now divide both sides by -1

Multiplication or Division property of order is used

$\frac{-x}{-1} \geq \frac{-\frac{9}{8}}{-1}$

Multiplication or Division property of order is used

$x\leq \frac{9}{8}$

You might be interested in

Jean and Sarah are buying tubs of ice cream. 2 scoops of ice cream are twice the price of 1 scoop of ice cream. Jean buys 4 tubs

liberstina [14]

Answer:

The answer is below

Step-by-step explanation:

Let x represent the cost of 1 scoop of ice cream. Since the cost of 2 scoops of ice cream are twice the price of 1 scoop of ice cream, therefore the cost of 2 scoops of ice cream = 2x

Jean buys 4 tubs with 2 scoops in them and 2 tubs with 1 scoop each. Therefore the money spent by Jean is:

Money spent by Jean = 4(2x) + 2(x) = 8x + 2x = 10x

Sarah buys 2 tubs of 2 scoops and 4 tubs of 1 scoop. The money spent by Sarah is:

Money spent by Sarah = 2(2x) + 4(x) = 4x + 4x = 8x

Sarah spends 2.50 € less than Jean. Therefore:

Money spent by Sarah = Money spent by Jean - 2.5

8x = 10x - 2.5

2x = 2.5

x = €1.25

Therefore the cost of 1 scoop of ice cream is €1.25, the cost of 2 scoops of ice cream is €2.50.

Money spent by Jean = 10x = 10(1.25) = €12.5

Money spent by Sarah = 8x = 8(1.25) = €10

3 0

3 years ago

Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =

vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

$a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2$

$a_1=8$

Find the value of $a_2$

For n=2

$a_2=2.9(a_1)-0.2(a_1)^2$

$a_2=2.9(8)-0.2(8)^2=10.4$

Find the value of $a_3$

For n=3

$a_3=2.9(a_2)-0.2(a_2)^2$

$a_3=2.9(10.4)-0.2(10.4)^2=8.528$

For n=4

$a_4=2.9(a_3)-0.2(a_3)^2$

$a_4=2.9(8.528)-0.2(8.528)^2=10.1858$

For n=5

$a_5=2.9(a_4)-0.2(a_4)^2$

$a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887$

therefore

The population alternates between increasing and decreasing

7 0

3 years ago

Read 2 more answers

5 points

Ede4ka [16]

Answer:

7.5in

Step-by-step explanation:

4 0

3 years ago

If it rained on 3 days out of 20 days on what percent of the days did it rain

Andrei [34K]

It rained on 15% of those days

3 0

3 years ago

Read 2 more answers

Solve the following equation for the variable x. ( 1/27 is a fraction )

igor_vitrenko [27]

The answer is,
$\frac{10935}{59048}$
Also equivalent to about, 0.185188.

5 0

3 years ago

Read 2 more answers