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3 years ago

What is the justification for each step in solving the inequality?

Mathematics

1 answer:

Fed [463]3 years ago

5 0

Step-by-step explanation:

$3x+\frac{5}{8}\geq 4x-\frac{1}{2}$

Subtract 5/8 on both sides

To subtract 5/8 we make the denominators same

$3x\geq 4x-\frac{1*4}{2*4}-\frac{5}{8}$

Addition or Subtraction property of order is used

$3x\geq 4x-\frac{9}{8}$

Subtract 4x on both sides

Addition or Subtraction property of order is used

$-x\geq -\frac{9}{8}$

Now divide both sides by -1

Multiplication or Division property of order is used

$\frac{-x}{-1} \geq \frac{-\frac{9}{8}}{-1}$

Multiplication or Division property of order is used

$x\leq \frac{9}{8}$

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What is the simplified form of the expression √450?

Darina [25.2K]

15<span>√2 is what I got for the answer.</span>

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3 years ago

Use a statistics calculator to find the area, in decimal form, rounded to four places after the decimal, under the (standard) No

Jlenok [28]

Answer:

a) 0.9641.

b) 0.0082

c) 0.0277

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

(a) ...to the left of 1.8.

p-value of Z = 1.8, which, looking at the z-table, is of 0.9641.

(b) ...to the right of 2.4.

1 subtracted by the p-value of Z = 2.4.

Looking at the z-table, Z = 2.4 has a p-value of 0.9918.

1 - 0.9918 = 0.0082, which is the answer.

(c) ...between 1.8 and 2.4.

p-value of Z = 2.4 subtracted by the p-value of Z = 1.8.

From itens a and b, we have both. So

0.9918 - 0.9641 = 0.0277

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3 years ago

Solve for x: x/25 > 5

WITCHER [35]

Answer:

x>125

Step-by-step explanation:

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3 years ago

Read 2 more answers

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Sveta_85 [38]

Answer:

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Step-by-step explanation:

should look like this

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3 years ago

A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w

DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 21.5, \sigma = 4.7$

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

$Z = \frac{X - \mu}{\sigma}$

$1.175 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.175*4.7$

$X = 27.0225$

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

$Z = \frac{X - \mu}{\sigma}$

$1.04 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.04*4.7$

$X = 26.388$

The lowest score that would meet the colleges requirement would be decreased to 26.388.

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3 years ago