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Elan Coil [88]
3 years ago
5

What is the justification for each step in solving the inequality?

Mathematics
1 answer:
Fed [463]3 years ago
5 0

Step-by-step explanation:

3x+\frac{5}{8}\geq 4x-\frac{1}{2}

Subtract 5/8 on both sides

To subtract 5/8 we make the denominators same

3x\geq 4x-\frac{1*4}{2*4}-\frac{5}{8}

Addition or Subtraction property of order is used

3x\geq 4x-\frac{9}{8}

Subtract 4x on both sides

Addition or Subtraction property of order is used

-x\geq -\frac{9}{8}

Now divide both sides by -1

Multiplication or Division property of order is used

\frac{-x}{-1} \geq \frac{-\frac{9}{8}}{-1}

Multiplication or Division property of order is used

x\leq \frac{9}{8}



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Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)
Gnom [1K]

Answer: Horizontal asymptote is \dfrac{1}{4} and vertical asymptotes are \pm \dfrac{1}{2i}

Step-by-step explanation:

Since we have given that

y=\dfrac{x^2-9}{4x^2+1}

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is 4x^2+1

Now,

4x^2+1=0\\\\4x^2=-1\\\\x^2=\dfrac{-1}{4}\\\\x=\pm \dfrac{1}{2i}

And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

y=\dfrac{1}{4}

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8 0
3 years ago
Which point would be a solution to the system of linear inequalities ?
brilliants [131]

Answer:

(12,-6)

Step-by-step explanation:

we have

y\leq \frac{4}{3}x+5 ----> inequality A

y\geq -\frac{5}{2}x+5 ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y  of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

-1\leq \frac{4}{3}(0)+5

-1\leq5 ----> is true

Inequality B

-1\geq -\frac{5}{2}(0)+5

-1\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

3\leq \frac{4}{3}(0)+5

3\leq5 ----> is true

Inequality B

3\geq -\frac{5}{2}(0)+5

3\geq 5 ----> is not true

therefore

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case 3) (-6,-6)

Inequality A

-6\leq \frac{4}{3}(-6)+5

-6\leq-3 ----> is true

Inequality B

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-6\geq 20----> is not true

therefore

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case 4) (12,-6)

Inequality A

-6\leq \frac{4}{3}(12)+5

-6\leq21 ----> is true

Inequality B

-6\geq -\frac{5}{2}(12)+5

-6\geq -25 ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

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