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3 years ago

Combine like terms to make a simpler expression 3z+z

Mathematics

1 answer:

ss7ja [257]3 years ago

7 0

Answer: 4z

All we do it add the variable z to 3z making it 4z

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1-1= what i need to know.

eduard

Answer:

0 is the answer same as 0+0=0

hope this helps

have a good day :

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A square pyramid is shown sitting on its base.

sesenic [268]

Answer:

312

Step-by-step explanation:

First we find the measure of the basea and that is 144 becuase 12x12

To find one side we do b*h over 2 and that is 7x12/2 which is 42 then we know that there are 4 more of those sides and we get 42*4 168

When we add 144+168 we will get 312

5 0

3 years ago

If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn

mash [69]

Let $a=\tan A$ and $b=\sin A$ . Then

$m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab$

$\implies m^2-n^2=4\tan A\sin A$

and

$mn=(a+b)(a-b)=a^2-b^2$

$\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}$

The expression under the square root can be rewritten as

$\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)$

Recall that

$\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A$

so that

$\tan^2A-\sin^2A=\sin^2A\tan^2A$

and assuming $\sin A>0$ and $\tan A>0$ , we end up with

$4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A$

so that

$m^2-n^2=4\sqrt{mn}$

as required.

5 0

3 years ago

Solve for y <br><br>2x - 5y = -12

Andreyy89

Answer:

-4

Step-by-step explanation:

just add both of the sides then divide

5 0

4 years ago

Which graph represents the relationship between the x-values and the y-values in the equation y = 3x + 2?

Gre4nikov [31]

Answer:

Step-by-step explanation

because 2 is the y intercept and 3 is the slope so you plot (0,2) than do the slope.

4 0

3 years ago