For which substance does (triangle) Hf = 0

Choose a Metal to Make Cookware

Ann [662]

Answer:

Explanation:

Your mom bumb it’s b

6 0

3 years ago

Click on the box to choose which compound has a greater difference in electronegativities of its members. Use the

4vir4ik [10]

Answer:

See the example below.

Explanation:

Let us make an example with a group of compounds to apply the general trends of electronegativities within families to find which compound has a greater difference in electronegativities.

Use this group.

a. HBr

b. HI

c. HF

d. HCl

e. H₂

Br, I, F, and Cl belong to the halogen family (group or column 17 of the periodic table).

Electronegativity is a relative measure of how strong an atom atracts the bonding electrons in a compound.

Since the strength of attracion of the valence electrons by the nucleus of an atom decreases as the size of the atom incease, in a family of elements (same group) the electronegativity decreases as you go down in the group.

The order of the halogens from top to bottom in the column in the periodic table is F, Cl, Br, and I.

Thus, the order of their electronegativiies is: F > Cl > Br > I. F is the most electronegative atom, and all those elements have higher electronegativy than H. (The electronegativiy of I is 2.66 and the electronegativity of H is 2.2). Thus, including H, the rank of the electronegativities is F > Cl > Br > I > H.

Thus, the greater difference in electronegativities is for HF (option a.).

Note, that the difference in electronegativites of the atoms of the molecule H₂ is zero, since both atoms have the same electronegativity.

3 0

3 years ago

Read 2 more answers

A certain liquid X has a normal boiling point of 108.30 °C and a boiling point elevation constant Kb=1.07 °C kg/mol. A solution

Fynjy0 [20]

Answer:

34,6g of (NH₄)₂SO₄

Explanation:

The boiling-point elevation describes the phenomenon in which the boiling point of a liquid increases with the addition of a compound. The formula is:

ΔT = kb×m

Where ΔT is Tsolution - T solvent; kb is ebullioscopic constant and m is molality of ions in solution.

For the problem:

ΔT = 109,7°C-108,3°C = 1,4°C

kb = 1.07 °C kg/mol

Solving:

m = 1,31 mol/kg

As mass of X = 600g = 0,600kg:

1,31mol/kg×0,600kg = 0,785 moles of ions. As (NH₄)₂SO₄ has three ions:

0,785 moles of ions× $\frac{1(NH_{4})_{2}SO_{4}}{3Ions}$ = 0,262 moles of (NH₄)₂SO₄

As molar mass of (NH₄)₂SO₄ is 132,14g/mol:

0,262 moles of (NH₄)₂SO₄× $\frac{132,14g}{1mol}$ = 34,6g of (NH₄)₂SO₄

I hope it helps!

7 0

4 years ago

NO FILES PLZ HELP!!

UNO [17]

I think it is B
Hope my answer help you?!?!?!?!?

7 0

3 years ago

Identify the products in the reaction HCl+NaOH=NaCl+H2O

valentina_108 [34]

NaCl and H2O.

The products are typically the elements/compounds on the right side of the equation or the right side of the arrow. The left side of the arrow would be the reactants of the equation.

Hope this helps!

5 0

3 years ago