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Mazyrski [523]
3 years ago
6

How many atoms are in a compound

Chemistry
2 answers:
borishaifa [10]3 years ago
8 0

Answer:

6.022×1023 atoms —1.00 mol of atoms.

Explanation:

Tcecarenko [31]3 years ago
7 0

Answer:

Compounds are made of two or more atoms of different elements,

Explanation:

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Which of the first 20 elements in a Periodic table has atoms with the greatest mass?​
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Calcium has the greatest mass of the first twenty elements with a mass of approximately 40.08
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Use Lewis theory to determine the chemical formula for the compound formed between Mg and Br. Group of answer choices Mg3Br2 Mg2
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Answer:

MgBr2

Explanation:

(Mg^2+) + (Br^1-)

For every Mg we need 2 Br to balance out the compound.

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2 years ago
The Nutrition Facts label for crackers states that one serving contains 19 g of carbohydrate, 4 g of fat, and 2 g of protein. Wh
sp2606 [1]

<u>Answer:</u> The amount of kilocalories contained in the given serving of crackes is 0.120 kCal

<u>Explanation:</u>

<u>As per the USDA:</u>

Carbohydrates provide 4 calories per gram, protein provides 4 calories per gram, and fat provides 9 calories per gram

We are given:

Mass of fat in the crackers = 4 g

Mass of carbohydrates in the crackers = 19 g

Mass of protein in the crackers = 2 g

Conversion factor used:  1 kCal = 1000 Cal

Applying unitary method:

  • <u>For Fat:</u>

1 gram of fat provides 9 calories

So, 4 gram of fat will provide = \frac{9}{1}\times 4=36Cal=0.036kCal

  • <u>For Carbohydrates:</u>

1 gram of carbohydrates provides 4 calories

So, 19 gram of carbohydrates will provide = \frac{4}{1}\times 19=76Cal=0.076kCal

  • <u>For Proteins:</u>

1 gram of proteins provides 4 calories

So, 2 gram of fat will provide = \frac{4}{1}\times 2=8Cal=0.008kCal

Total kilocalories per serving = [0.036 + 0.076 + 0.008] kCal = 0.120 kCal

Hence, the amount of kilocalories contained in the given serving of crackes is 0.120 kCal

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3 years ago
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Số oxi hóa của các nguyên tố: Fe(OH)2; Fe(OH)3; FexOy; Zn(OH)2 là gì
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Answer:

esfsef

Explanation:

esfsefseF

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2 years ago
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