Which of the following sets of ordered pairs represents a function?

1 answer:

3 0

{(-1,3),(-1,4),(-1,5),(-1,6)} is the set from the given question which is a set of ordered pairs representing a function.

<h3>What is ordered pair?</h3>

An ordered pair (a, b) in mathematics is a group of two things. The pair's order of objects matters because the ordered pair (a, b) differs from the ordered pair (b, a) unless a = b. (By contrast, an unordered pair of a and b equals an unordered pair of b and a.)

Ordered pairs are also known as 2-tuples, or sequences (or, in computer science, occasionally, lists) of length 2. Sometimes referred to as 2-dimensional vectors, ordered pairs of scalars. Technically speaking, this is a misuse of the term because an ordered pair need not be a component of a vector space. An ordered pair's entries may be other ordered pairs, allowing for the recursive definition of ordered n-tuples (ordered lists of n objects).

Learn more about ordered pairs

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Write your answer as a whole number and remainder.530/34

arsen [322]

Hey, Zalah. For my answer, I simplified 530/34. Which equals 15.58824. Hope this helps! :)

3 0

3 years ago

Given the data points, (x, y) of a linear function: (2, 11), (4, 10), (6, 9), (12, 6), what is the function? What is the slope?

NeX [460]

Answer:

The function is $y~=~12 ~-~ 0.5 \cdot x$ .

The slope is $m=-0.5$ .

The y-intercept is $b=12$ .

Step-by-step explanation:

Our aim is to calculate the values m (slope) and b (y-intercept) in the equation of a line :

$y=mx+b$

We have the following data:

$\begin{array}{c|cccc}x&2&4&6&12\\y&11&10&9&6\end{array}$

To find the line of best fit for the points given, you must:

Step 1: Find $X\cdot Y$ and $X\cdot X$ as it was done in the table below.

Step 2: Find the sum of every column:

$\sum{X} = 24 ~,~ \sum{Y} = 36 ~,~ \sum{X \cdot Y} = 188 ~,~ \sum{X^2} = 200$

Step 3: Use the following equations to find b and m:

$\begin{aligned} b &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 36 \cdot 200 - 24 \cdot 188}{ 4 \cdot 200 - 24^2} \approx 12 \\ \\m &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 4 \cdot 188 - 24 \cdot 36 }{ 4 \cdot 200 - \left( 24 \right)^2} \approx -0.5\end{aligned}$